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Maksim231197 [3]
3 years ago
8

Number 10 plzz???????

Mathematics
1 answer:
WARRIOR [948]3 years ago
7 0
%error=(6.5g/mol - 7g/mol)/(7g/mol) * 100= 7.14% error
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Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product o
Keith_Richards [23]

Answer:

  32.1 g

Step-by-step explanation:

In each 3 grams of C, there are 2 grams of A and 1 gram of B. So, for some amount C, the amount remaining of A is 40 -(2C/3), and the amount remaining of B is (50 -C/3). Since the reaction rate is proportional to the product of these amounts, we have ...

  C' = k(40 -2C/3)(50 -C/3) = (2k/9)(60 -C)(150 -C) . . . for some constant k

This is separable differential equation with a solution of the form ...

  ln((150 -C)/(60 -C)) = at + b

We know that C(0) = 0, so b=ln(150/60) = ln(2.5). And we know that C(10) = 20, so ln(130/40) = 10a +ln(2.5) ⇒ a = ln(1.3)/10

Then our equation for C is ...

  ln((150 -C)/(60 -C)) = t·ln(1.3)/10 +ln(2.5)

__

For t=20, this is ...

  ln((150 -C)/(60 -C)) = 2ln(1.3) +ln(2.5) = ln(2.5·1.3²) = ln(4.225)

Taking antilogs, we have ...

  (150 -C)/(60 -C) = 4.225

  1 +90/(60 -C) = 4.225

  C = 60 -90/3.225 ≈ 32.093 . . . . . grams of product in 20 minutes

In 20 minutes, about 32.1 grams of C are formed.

7 0
3 years ago
1: 2(y+6)=?<br> 2: 6-(-6+2)=?<br> What is the property of equation?
Citrus2011 [14]
1: 2y+12

2: 6 +6 -2
+12 -2
= 10
5 0
3 years ago
4/9+3/10= what's the answer please​
Marta_Voda [28]

Answer:

67/90

Step-by-step explanation:

no explanation

3 0
3 years ago
Read 2 more answers
−4+8x)+3&gt;x−4?<br><br> x&gt;16<br><br> x&lt;−1<br><br> x&lt;−323<br><br> x&gt;433
pentagon [3]

Answer:

x > 4/33

Step-by-step explanation:

(-4 +8x) +3> x/-4

8x - 1 > x/-4

-32x + 4 < x

4 < 33x

4/33 < x

6 0
2 years ago
Show all work to factor x^4 − 17x^2 + 16 completely.
FrozenT [24]

Answer:

it looks like it is completely factored out to me at least there is a high possibility I am wrong because that looks complicated I wish I could help

6 0
3 years ago
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