I pretty sure that the answer is 1.
Answer:
Step-by-step explanation:
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( thats what i found on the internet, hope this helps :) ! )
Answer:
(a) 90°
(b) 8.75
(c) 63.75°
(d) 26.25°
Step-by-step explanation:
(a) A radius to a point of tangency is always perpendicular to the tangent line there. Q is the point of tangency of line PQ, so the segment RQ from the center of the circle, R, to that point makes a 90° angle with PQ. Angle RQP is 90°.
(b) The sum of the acute angles of a right triangle is 90°, so ...
(5x +20)° + (3x)° = 90° . . . . . the sum of the acute angles is 90°
8x + 20 = 90 . . . . . . . . . . . . simplify, divide by °
8x = 70 . . . . . . . . . . . . . . . . . subtract 20
70/8 = x = 8.75 . . . . . . . . . . . divide by the coefficient of x
(c) ∠QRP = (5x+20)° = (5·8.75 +20)° = 63.75° . . . . . use the value of x in the expression for the angle measure
(d) ∠RPQ = (3x)° = (3·8.75)° = 26.25° . . . . . use the value of x in the expression for the angle measure
Answer:
24+8i/3=68+2i/9
Step-by-step explanation: