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riadik2000 [5.3K]
3 years ago
10

What is the equation of a parabola with a vertex at (-2, 0) and a directrix x = -4.

Mathematics
1 answer:
slava [35]3 years ago
5 0

Answer:


Step-by-step explanation:

This is a horizontal parabola opening to the right, with vertex at (-2,0) and directrix at x = -4 (which is to the left of the vertex).  The general equation of such a parabola is 4p(x-h) = (y-k)^2, where p is the number of horizontal units between directrix and vertex; here this quantity is 2.

Substituting known values into the general equation, we get:

4(2)(x+2) = (y-0)^2, or 8(x+2) = y^2.

Check:  does (-2,0) satisfy the above equation (as it must)?  8(-2+2) = 0^2   YES.

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[100 POINTS] What is the measure of the arc from A to B that does not pass through C?
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Applying the inscribed angle theorem, the measure of arc AB that doesn't go through point C is: 100 degrees.

<h3>What is the Inscribed Angle Theorem?</h3>

Based on the inscribed angle theorem, if ∅ is the inscribed angle measure, the measure of the central angle subtended by the same arc equals 2(∅).

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To eliminate the y-terms and solve for x in the fewest steps, by which constants should the equations be multiplied by before ad
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Answer:

use -9 to multiply the first equation

use -4 to multiply the second equation.

Step-by-step explanation:

5x-4y=28.....eqn (1)×-9

3x-9y=30....eqn(2)×-4

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therefore, -33x÷33 =-132÷-33

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5(4)-4(-2)=28.

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