All categories

3 years ago

The length and the breadth of a rectangular piece of land are 500m and 300m respectively. Find it’s area

Mathematics

2 answers:

garik1379 [7]3 years ago

8 0

It’s area would be 150000m because area is LxW so (500x300)

katrin [286]3 years ago

6 0

Area of a rectangle = Length x Breadth
The required area = 500 x 300
= 150000 m^2

You might be interested in

There are 64 pretzels in a 16 ounce bag of chocolate covered pretzels.

FromTheMoon [43]

16:64
5:x (Cross Multiply)
16x = 64*5
16x = 320 (Then Divide both sides by 16 to isolate x)
x= 20

5 0

3 years ago

How many cards are in a standard deck of cards? What are their colors?

sergey [27]

Answer:

A standard deck of cards consists of 52 cards. The colors are usually black for the spades and clubs and red for the hearts and diamonds.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Emily is entering a bicycle race for charity her mother pledges $0.40 every 0.25 miles she bikes only bikes 15 miles how much wi

ladessa [460]

The answer is 24 dollars

6 0

3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

Read 2 more answers

Find the product of the given polynomials. (5x + 8 – 6r) (4 + 2r – 7)

Inessa05 [86]

Answer:

-12r² + 10xr - 15x + 34r - 24

Step-by-step explanation:

1. Organize it, variables first - as well as adding constants such as 4 and -7

(5x - 6r + 8) (2r - 3)

2. Start by multiplying the 5x by (2r - 3), then -6r, followed by 8

(10xr - 15x) + (-12r^2 + 18r) + (16r - 24)

3. Simplify

10xr - 15x - 12r² + 18r + 16r - 24

4. Order by greatest to smallest factorial

-12r² + 10xr - 15x + 18r + 16r - 24

5. Combine like variables

-12r² + 10xr - 15x + 34r - 24

6 0

2 years ago