What is the probability of rolling a number less than or equal to 8 with two dice, given that at least one of the dice must show
a 6?
A. 9/11
B. 4/11
C. 2/11
D. 7/11
1 answer:
The answer is C because you can only roll an 8 with a show of 6 when you roll 6 and 1 which gives 7 and 6 and 2 which gives 8
You might be interested in
2/9-x/5
10-9x/45
Is your answer
6t - 20 - 32u
6(6) - 20 - 32(1/4)
36 - 20 - 8
36 - 20 = 16 - 8 ⇒8
The final answer is 8.
3.96666666667 so technically it .96
28/57*100=49% I would like to think that is the correct procedure and answer
They can finish in 18 different ways
