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Dafna1 [17]
4 years ago
9

Original price: $33.75, markdown 75%

Mathematics
2 answers:
Kamila [148]4 years ago
6 0

Answer:

8.44 / (8.4375)

Step-by-step explanation:

1) Multiply the original price with .75, 75% as a decimal

25.3125

2) Subtract markdown price: 25.3125 from 33.75

8.4375

3) You could round to $8.44

Cloud [144]4 years ago
4 0

Answer:

$25.31

Step-by-step explanation:

If you multiply 33.75 by .75 you get your answer.

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Which diagram best shows how fraction bars can be used to evaluate One-half divided by one-fourth?
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Answer:

the onw haldf

Step-by-step explanation:

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4 years ago
If I sent 5 emails to my friends and they each send 5 email & this happens 2 more times, which expression shows the total nu
kvasek [131]

Answer:

(5+5)x2

Step-by-step explanation:

I think this is it, as for you said a person sent 5 emails to 5 friends, so 5 so far. Then they sent 5 mails, 5+5=10. This happened 2 times so 10x2.

6 0
3 years ago
The sum of two numbers is 69 and their difference is 17. what are the two numbers?
antoniya [11.8K]

Answer:

41

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
How do you use the limit comparison test on this particular series?<br>Calculus series tests​
barxatty [35]

Compare \dfrac1{\sqrt{n^2+1}} to \dfrac1{\sqrt{n^2}}=\dfrac1n. Then in applying the LCT, we have

\displaystyle\lim_{n\to\infty}\left|\frac{\frac1{\sqrt{n^2+1}}}{\frac1n}\right|=\lim_{n\to\infty}\frac n{\sqrt{n^2+1}}=1

Because this limit is finite, both

\displaystyle\sum_{n=1}^\infty\frac1{\sqrt{n^2+1}}

and

\displaystyle\sum_{n=1}^\infty\frac1n

behave the same way. The second series diverges, so

\displaystyle\sum_{n=0}^\infty\frac1{\sqrt{n^2+1}}=1+\sum_{n=1}^\infty\frac1n

is divergent.

4 0
4 years ago
Find each difference.
serg [7]

Answer: -9s^2 + 4s-2

Step-by-step explanation:

(-6s^2 +12s-8)-(3s^2 + 8s-6)\\\\=-6s^2 + 12s-8-3s^2 - 8s+6\\\\=\boxed{-9s^2 +4s-2}

3 0
2 years ago
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