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3 years ago

Graph the linear equation. Find three

Mathematics

1 answer:

Sever21 [200]3 years ago

6 0

Y=1/3x+2
(-6,0)
(0,2)
(6,4)

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Factiorize; y*2-4,is the question

Viktor [21]

Answer:

(y - 2)(y + 2)

standard factorization!

tadah

4 0

2 years ago

Jen Butler has been pricing Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 79.

xxMikexx [17]

<u>Answer:</u>

Price of the adult's ticket = $13

Price of a child's ticket = $ 10

<u>Step-by-step explanation:</u>

Given:

Cost of train fares for Three adults and four children = $79

Cost of train fares Two adults and three children = $ 56

To Find:

Price of the adult's ticket and the price of a child's ticket =?

Solution:

Let the cost of one adult's ticket be x and

Let the cost of one child's ticket be y

Then

Three adults and four children must pay $ 79 be

3x + 4y = 79-----------------------------------------------(1)

Two adults and three children must pay $56

2x + 3y = 56----------------------------------------------(2)

multiply eq(1) by 2, we get

6x + 8y = 158----------------------(3)

multiply eq(2) by 3, we get

6x + 9y = 168----------------------(4)

Subracting (3) from (4)

6x + 9y = 168

6x + 8y = 158

(-) (-) (-)

------------------------------

0x + y = 10

------------------------------

y=10

Now substitute the value of y in eq (1) to get the value of x

3x + 4(10)= 79

3x + 40 = 79

3x = 79 - 40

3x = 39

x = $\frac{39}{3}$

x= 13

3 0

3 years ago

Please help! Will mark brainliest!

Oksi-84 [34.3K]

Sorry, misunderstood question, answer beneath me much better.

8 0

2 years ago

Read 2 more answers

The game of Connex contains one 4-unit piece, two identical 3-unit pieces, three identical 2-unit pieces and four identical 1-un

Aleks [24]

Answer: 277 ways

Step-by-step explanation:

Let’s start bycreating 10-unit pieces using the 4-unit piece.

The arrangements are:

1). 4-3-3 (3 permutations)

2). 4-3-2-1 = 4! = 24 permutations.

3). 4-3-1-1-1 (5*[4!/(3!1!)]

= 5*4

= 20permutations

4). 4-2-2-2 (4 permutations)

5). 4-2-2-1-1 (5 *[4!/(2!2!)]

= 5*6

= 30 permutations

6). 4-2-1-1-1-1(6*[5!/(4!1!)]

= 6*5

= 30 permutations

Let’s-consider the arrangements using one or more3-unit pieces and no 4-unit piece:

7). 3-3-2-2 (4!/(2!2!)

8). 3-3-2-1-1 (5*(4!/(2!2!)

= 5*6

= 30 permutations.

9). 3-3-1-1-1-1 (6!/(4!2!) = 0

10). 3-2-2-2-1 (5*4!/(3!1!)

= 5*4

= 20permutations

11). 3-2-2-1-1-1 (6*5!/(3!2!)

= 6*10

= 60 permutations

Finally we would look at the arrangements using only 1-and 2-unit pieces:

12). 2-2-2-1-1-1-1 (7!/(4!3!)

= 35 permutations

add them all up:

(3 + 24 + 20 + 4) + (30 + 30 + 6 + 30) + (15 + 20 + 60 + 35)

=51 + 96 + 130

= 277ways

5 0

2 years ago

Can somebodt please help me

irakobra [83]

can someone help me we out

4 0

3 years ago