The amount of kilograms of each type of original fruit juice weighs; 12 kg of Apple and 6 kg of grape
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The concentrations of apple and grape juice in the two different juice types are given as;
Juice A:
(2/3) apple
(1/3) grape
Juice B:
(1/3) apple
(2/3) grape
Let a be how much juice A is in the mixture;
Let b be how much juice B is in the mix.
Thus;
²/₃a + ¹/₃b = 10 ------(eq 1)
¹/₃a + ²/₃b = 8 ------(eq 2)
Solving both equations simultaneously gives us;
a = 12 and b = 6
Thus, the amount of kilograms of each type of original fruit juice weighs; 12 kg of Apple and 6 kg of grape
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Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet, 
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :
Putting all the values,
.....(1)
For maximum height, put
Put t = 1.875 in equation (1)
So, the maximum height reached by the ball is 61.25 m.
Answer:
Q1: 12.5
Q3: 16
IQR: 3.5
Step-by-step explanation:
Mean : 14.25
Median : 13.5
Mode : 13, 12
Range: 6
Minimum :12
Maximum: 18
Count n: 8
Sum: 114
Quartiles Quartiles:
Q1 --> 12.5
Q2 --> 13.5
Q3 --> 16
Interquartile
Range IQR: 3.5
Outliers: none
Answer:
i can see it
Step-by-step explanation:
Answer:
1:8
Step-by-step explanation:
1 hour for every 8 ounces gives a 1:8 ratio
