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3 years ago

11

Please help ♡♡♡♡♡♡♡

1 answer:

lions [1.4K]3 years ago

5 0

Step-by-step explanation:

$\angle AOB$ and $\angle BOC$ are linear pair angles.

$\therefore m\angle AOB + m\angle BOC = 180° \\ \therefore \: 3x + 124 \degree + 6x + 29 \degree = 180° \\ \therefore \: 9x + 153 \degree = 180° \\ \therefore \: 9x = 180° - 153 \degree \\ \therefore \: 9x = 27 \degree \\ \therefore \:x = \frac{27 \degree }{9} \\ \huge \pink{ \boxed{\therefore \:x =3 \degree }} \\ \\ \because \: m\angle BOC =6x + 29 \degree \\ \therefore \: m\angle BOC =6 \times3 \degree + 29 \degree \\ \therefore \: m\angle BOC = 18\degree + 29 \degree \\ \\ \huge \red{ \boxed{\therefore \: m\angle BOC = 47 \degree }}$

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An urn contains six red balls and four green balls. A sample of seven balls is selected at random.

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3 years ago

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

3 years ago