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Anastasy [175]
3 years ago
6

An urn contains six red balls and four green balls. A sample of seven balls is selected at random.

Mathematics
1 answer:
KIM [24]3 years ago
5 0

There are 10 balls in the Urn Total.

Red: 6

Green: 4

Question One: The probability that five red and two green is selected is likely. (as that is over half for both)

Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.

Question Three: At least four is likely, as  there is more red then green in the Urn.

Hope I helped!

(Mark Brainliest if you can please!)

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Putting the values, we get:

0.74\pm 1.645(\sqrt{\dfrac{0.74(1-0.74)}{500}}) = 0.74\pm 0.0322\\\\=(0.7078,0.7722)

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