3 years ago

What is the value of x in the figure? Enter your answer in the box.

Mathematics

2 answers:

Andrews [41]3 years ago

4 0

Answer: 29

Step-by-step explanation:

Add the right angle which would equal 90 degrees with the 61 degrees. Now you get 151. Subtract 151 from 180, which is half of the circle. Now you have 29 degrees.

andreyandreev [35.5K]3 years ago

3 0

Answer:

x=29

Step-by-step explanation:

x+61=90

61-61

90-61

x=29

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2 years ago

I need help plzzzz percent equations blank% of $30 =3

Lyrx [107]

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Step-by-step explanation:

Hello I can help you with this question. Lets start.

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2 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

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2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

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3 years ago

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SVETLANKA909090 [29]

It would be A
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3 years ago