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Lilit [14]
3 years ago
8

Find the solution of this system of equations.

Mathematics
1 answer:
Drupady [299]3 years ago
4 0
<span>{x= 0 + y     </span>⇒ x=y<span>
{3x + 12y= 15

3y + 12y = 12
15y = 15
y = 1

x = y = 1

Answer: x=1,  y=1</span>
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The value of the solid's surface area is equal to the value of the solid's volume. Find the value of x. We know the length is 9
Lerok [7]

Given:

The value of the solid's surface area is equal to the value of the solid's volume.

Length(l) = 9 units

width(b) = 4 units

Height(h) = x units

To find:

The value of x.

Solution:

Solid's surface area is

Area=2(lb+bh+hl)

Area=2(9\times 4+4\times x+x\times 9)

Area=2(36+4x+9x)

Area=2(36+13x)

Area=72+26x

Volume of solid is

Volume=l\times b\times h

Volume=9\times 4\times x

Volume=36x

Solid's surface area = Volume of solid

72+26x=36x

72=36x-26x

72=10x

Divide both sides by 10.

7.2=x

Therefore, the value of x is 7.2.

4 0
3 years ago
No links please :(
kotegsom [21]
A.


Store A has sold the most wristbands
5 0
2 years ago
What is the measure of ∠A, the exterior angle of the triangle shown below? F. M∠A = 92°, because 180 – (50 + 38) = 92. G. M∠A =
hjlf

Answer: A is 88

Step-by-step explanation:

Sum of all angles is 180 degree.

Let the third interior angle be x.

38+50+x=180

88+x=180

x= 92

A and X are in linear pair.

A+X=180

A+92=180

A=88

3 0
2 years ago
What is the following number in the sequence? What is the sequence's equation?<br> 9, 15, 21, 27, __
fenix001 [56]
Its going up by 6, the answer is 33
8 0
3 years ago
A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi
34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{X}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

\sigma_{X}=\sqrt{n}\sigma

It is provided that:

\mu=\$27\\\sigma=\$18\\n=310

As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let <em>s</em> denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding <em>z-</em>value is, -2.33.

Compute the value of <em>s</em> as follows:

z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

5 0
2 years ago
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