Answer:

Step-by-step explanation:
Option 1:
Using the following rule:

Put in our expression,
a = 2
n = 3
m = 2


Option 2:
Using the following rule:

Since our expression is the same as multiplying 2³ with itself, we can write it as a multiplication.

If we compare this with
, we can see that
a = 2
n = 3
m = 3 (in this case, n and m are equal)


Answer: 
Answer:
75600k^4 m^4 Hope that help !
Step-by-step explanation:
1. Take out the constants (25×7×18×24) kkkkmmmm
2. Simplify 25×7=175 (175×18×24)kkkkmmmm
3. Simplify 175×18=3150 (3150×24)kkkkmmmm
4. 3150×24= 75600kkkkmmmm
5. The answer would be 75600k^4 m^4
Answer:
x = 1
z = 1/2
Step-by-step explanation:
z = 3/y
z = 3/6
z = 1/2
x = 2z
x = 2(1/2)
x = 1
<h3><u>(2x - 5)(4x - 3)</u></h3>
The AC method, also known as splitting the middle, can be shown like this:
8x^2 - 26x + 15
<em><u>Check factors of 120.</u></em>
1 * 120
-1 * -120
2 * 60
-2 * -60
3 * 40
-3 * -40
5 * 24
-5 * -24
6 * 20
-6 * -20 (these factors, when added together, are equal to the middle term, and thus splitting the middle term is possible.)
<em><u>Split the middle term.</u></em>
8x^2 - 6x - 20x + 15
<em><u>Group in terms of 2.</u></em>
(8x^2 - 6x) - (20x + 15)
<em><u>Factor each binomial.</u></em>
2x(4x - 3) - 5(4x - 3)
<em><u>Rearrange the terms.</u></em>
(2x - 5)(4x - 3)