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Ratling [72]
3 years ago
9

4. A study of 30 fathers was completed in which the fathers were asked the highest level of education they had completed. 10 com

pleted only elementary school, 10 completed elementary school and high school; 7 completed elementary school, high school and college; 3 completed elementary school, high school, college and graduate school. What was the cumulative percentage of fathers who completed only elementary school?
Mathematics
1 answer:
zaharov [31]3 years ago
7 0

Answer:

The cumulative percentage of fathers who completed only elementary school is nearle 33%.

Step-by-step explanation:

Among 30 fathers:

  • 10 completed only elementary school;
  • 10 completed elementary school and high school;
  • 7 completed elementary school, high school and college;
  • 3 completed elementary school, high school, college and graduate school.

You can fill these numbers into the table:

\begin{array}{cccc}&\text{Frequency}&\text{Cumulative frequency}&\text{Cumulative percentage}\\\text{Elementary school}&10&10&\approx 33\%\\\text{El. and high school}&10&20&\approx 67\%\\\text{El., high schools and college}&7&27&90\%\\\text{El., high, college and grad. sch.}&3&30&100\%\end{array}

The cumulative percentage of fathers who completed only elementary school is nearle 33%.

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FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
Can you help me find each measure?
madam [21]

Answer:

Step-by-step explanation:

1. the measure for HJ you can already see, start from h and draw a line to J. The measure shows 63 degrees.

2. start at F and draw a line to G first. the measure shows 65 degrees. Now continue the line from where you stopped at G, to H. There's no measure but you can see it is in a semicircle. A semicircle is 180 degrees andthe other two angles are 63 and 65.

So...

180=63+65+GH

subtract to get GH

180-63-65= 52

so the measure GH is 52 degrees. The full measure you are trying to find is FGH thought. So ad the 65 and the 52.

FGH =117 degrees.

3. The meaure is CDE. CD as you can see is a right angles, so 90 degrees. But there is no measure for DE. If you look to the angle vertical from DE which is BA. It measures 40 degrees. DE and BA are vertical so they are congruent. If DE equals 40  and CD equals 90, put them together and you get 130.

CDE= 130 degrees

4. Next measure is BCD. We already know CD is a 90 degree angle but BC is blank. You can see the measure BCD is in a semi circle. A semicircle equals 180, CD equals 90, and BA equals 40

so...

180= 90+40+BC

so subtract

180-90-40= 50

BC =50

so add BC=50 and CD=90. SO, BCD is 140 degrees.

5.The angle LMN is next. MN is 30 but LM is blank. LMN is in a semi circle.

A semicircle is 180 degrees.

so...

180=105+30+LM

subtract

180-105-30=45

LM = 45

Add LM=45 and MN=30

LMN is 75 degrees.

6.The last angle is LNP

If you look at it MP is a semi circle, so 180 degrees. And LM is 45 from our last question. so 180 +45=225

LNP=225

hope this helps

4 0
3 years ago
Solve for C<br><br> C<br> — - 4.3 = 11.5 <br> 2
Maslowich

Answer:

The correct answer is,

c = 31.6

7 0
3 years ago
PLEASE HELP ME! I am stuck on 12 and 13. Thanks in advanced! :D
Juliette [100K]

Answer:

75, 105

Step-by-step explanation:

12. 180-105 = 75

13. 105

8 0
2 years ago
Read 2 more answers
9 + (1/2)^4x48 I couldn't find a correct answer for this.
Rufina [12.5K]
9+ (\dfrac{1}{2} )^4 \times 48 = 9 + \dfrac{1}{16} \times 48  = 9 + 3 = 12


Answer: 12
3 0
3 years ago
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