5/(6x-2)=-1/(x+1)
You have to multiply both sides by the denominators so it becomes:
5*(x+1)=-1*(6x-2)
5x+5=-6x+2
3=x
This applies to the second one as well, if you need any more help, feel free to message me :)
1) Add 9 to both sides. On the left side of the equal sign it will cancel out. on the right side of the equal sign because it is now a different sign equation you subtract -193 from 9 which equals -184
2) now you are left with to= -184
to get the variable by itself you need to divide both sides by 4. on the left side of the equal sign you have p by itself now , on the right you divide -184 by 4 and your answer comes out to be p= -46
3) p= -46 is your final answer!
Answer:
± 
, 
Step-by-step explanation:
See the attached image
This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are: 
that correspond to the force of resistance on the mass by the action of the spring and 
that is an external force with unknown direction (that does not specify in the enounce).
For determinate we can use Hooke's Law given by the formula 
where 
correspond to the elastic constant of the spring and 
correspond to the relative displacement of the mass-spring system with respect of his rest state.
We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...
Now we apply Newton's 2nd Law and obtaint that...
± = 
Finally... ±
We know from the problem that there's not initial displacement and initial velocity, so... and
Finally the Initial Value Problem that models the situation describe by the problem is
Answer: Choice A. 
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Work Shown:
