The two way table that correctly displays the given data is; Option B
<h3>How to Interpret Two - way Tables?</h3>
We are given that;
39 people chose chicken as the main dish,18 wanted potatoes.
32 people chose rice as a side dish, 6 chose fish as the main dish.
A total of 8 people chose a vegetarian meal with potatoes,
A total of 10 people chose fish as their main dish.
From the given parameters above, when we look at all the 4 two way tables attached in the image, we will see that only the second option is the correct one.
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The mole fraction of the non-volatile solute in the solution is 0.13.
<h3>Mole fraction of solute </h3>
Using law of vapor pressure formula
Mole fraction of the non-volatile solute=Vapor pressure of the pure acetone-Vapor pressure of the solution /Vapor pressure of the pure acetone
Where:
Vapor pressure of the pure solvent (acetone) =266 torr
Vapor pressure of the solution =232torr
Mole fraction of solute = ?
Let plug in the formula
Mole fraction of the non-volatile solute=266-232/266
Mole fraction of the non-volatile solute=34/266
Mole fraction of the non-volatile solute=0.127
Mole fraction of the non-volatile solute=0.13 (Approximately)
Inconclusion the mole fraction of the non-volatile solute in the solution is 0.13.
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The excess reactant in the combustion of 211 g of methane in an open atmosphere is oxygen, O₂
<h3>What is a combustion reaction? </h3>
A combustion reaction is a reaction in which a substance burns in air (oxygen) to produce carbon dioxide and water.
<h3>Combustion of methane </h3>
Methane combust in air (oxygen) to produce carbon dioxide and water according to the following equation:
CH₄ + 2O₂ —> CO₂ + 2H₂O
From the question given above, we were told that 211 g of methane combust in an open atmosphere. This simply means that the amount of oxygen will be very high.
Therefore, we can conclude that oxygen will be the excess reactant since the reaction is carried out in an open atmosphere.
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Is this a true or false queston
