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3 years ago

I’m confused plz help!!

Mathematics

1 answer:

Xelga [282]3 years ago

3 0

The explanation is on the picture I attached!

Hope you get it!

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Simplify 3^2 x 3^4 x 3^6

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The answer is 531441

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What makes composing functions different from doing an arithmetic operation of two functions such as adding or dividing them?

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Answer:

the answer is that one tells about nomadic responses

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3 years ago

Please help!!!!!!!!!!!!!!!

icang [17]

Answer:

im not sure

Step-by-step explanation:

go to www.analyzemath.com

4 0

3 years ago

8. Mohan wants to buy a trapezium shaped field.

mojhsa [17]

Answer:

<em>The length of the side along the river is 140 m</em>

Step-by-step explanation:

<u>Equations</u>

To solve the problem, we need to recall the area of a trapezium is:

$\displaystyle A=\frac{b1+b2}{2}.h$

Where b1 and b2 are the lengths of the parallel sides and h is the height of the trapezium.

The field to be bought by Mohan has a trapezium shape with a side along the road of side x and a side along the river of side 2x, as stated in the problem.

Knowing the height is h=100 m, and the area is 10500 m2:

$\displaystyle \frac{x+2x}{2}\cdot 100=10500$

Simplifying:

$\displaystyle (3x)\cdot 50=10500$

$150x=10500$

Dividing by 150:

$x = 10500 / 150 = 70$

x = 70 m

2x = 140 m

The length of the side along the river is 140 m

8 0

2 years ago

Below are the data collected from two random samples of 500 American adults on the number of hours they spend doing leisure and

ElenaW [278]

From the question we are told that:

Total Sample size n=500

Dan's mean \=x_D= 3hr

Bret's mean \=x_D= 4hr

Generally, the Total hours spent doing leisure and sports activities is mathematically given by

For Sample A

$T_a=(1*70)+(2*90)+(3*135)+(4*140)+(5*65)\\\\$

$T_a=1540 hours$

For Sample B

$T_b=(1*80)+(2*80)+(3*130)+(4*135)+(5*75)$

$T_b=1545$

Therefore

Average Time spent doing leisure and sports activities by an American Adult

For Sample A

$T_A=\frac{T_a}{n}$

$T_A=\frac{1540}{500}$

$T_A=3.08$

$T_A \approx 3$

For Sample B

$T_A'=\frac{T_b}{n}$

$T_A'=\frac{1545}{500}$

$T_A'=3.09$

$T_A' \approx 3$

Therefore

Dan is Correct because 3.08 or 3.09 is approximately equal to 3

7 0

3 years ago