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Mrrafil [7]
3 years ago
11

Which expression is equivalent to (2r2+r - 1) – (3r2+48 - 5)?

Mathematics
1 answer:
BigorU [14]3 years ago
7 0

Answer:

-r^2-3r+4

Step-by-step explanation:

The question is to simplify the expression  (2r^2+r-1)-(3r^2+4r-5)

First, we can eliminate the 2nd parenthesis expression by changing signs of all the terms since there is a "-" sign in front. Then we add the "Like Terms". The process is shown below:

(2r^2+r-1)-(3r^2+4r-5)\\=2r^2+r-1-3r^2-4r+5\\=-r^2-3r+4

The first answer choices (has some typos) is correct. The correct answer is  -r^2-3r+4

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Answer:

16

Step-by-step explanation:

To solve this equation, we need the formula for perfect squares:

  • (a + b)^2 = a^2 + 2ab + b^2

or

  • (a - b)^2 = a^2 - 2ab + b^2 <em>this is the formula we will use because the signs match the one in the question</em>.

Knowing these, we can set up an equation that assumes that the answer we will end up with is a perfect square.

Work:

(v - x)^2 = v^2 -8v + x^2

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(v - x)^2 = v^2 - 8v + x^2 (I replaced 2ab with 8v because I'm setting up this question to be a perfect square).

(v - x) (v - x) = v^2 - 8v + x^2

  • multiply the left side. Remember that your answer will not be v^2 + x^2, but v^2 - 2vx +x^2.

v^2 - 2vx + x^2 = v^2 + 8v + x^2

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2vx = 8v

  • divide by 2v and you will have your value for x.

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(v - 4)^2 = v^2 - 8v + 16

Our final answer is 16.

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