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olga2289 [7]
3 years ago
8

Drainage tubing comes in large rolls. At your hardware store, you cut tubing to the lengths the customers want. You also provide

customers with the volume of their tubing because they need to fill tubing with gravel as they install it. The tubing’s inside radius is 2 inches. Which of the following is an expression for the volume of L feet of drainage tubing, in cubic feet?
Mathematics
2 answers:
Marrrta [24]3 years ago
8 0

Answer:

0.09 L cubic feet

Step-by-step explanation:

We are given that

Radius of tubing's inside=2 in

We have to find the expression for the volume of L feet of drainage tubing in cubic feet.

Length of tube=L feet

1 foot=12 in

2 in=\frac{2}{12}=\frac{1}{6} feet

We know that volume of cylinder=\pi r^2h

Where r=Radius of cylinder

h=Height of cylinder

Substitute the values in the formula then we get

Volume of drainage tubing=3.14\times (\frac{1}{6})^2\times L

Volume of drainage tubing=0.09L cubic feet

This is required expression for the volume of L feet of drainage tubing.

MrRa [10]3 years ago
4 0

Answer: \frac{1}{36}\pi L

Step-by-step explanation:

The formula for calculate the volume of a cylinder is:

V=\pi r^2h

Where "r" is the radius and "h" is the height.

Make the conversion from inches to feet. Since 1\ ft=12\ in,you get:

(2\ in)(\frac{1\ ft}{12\ in})=\frac{1}{6}\ ft

So in this case you  can identify that:

r=\frac{1}{6}\\\\h=L

Then, substituting them into the formula and simplifying you get:

V=\pi(\frac{1}{6})^2L\\\\V=\frac{1}{36}\pi L

Therefore, the expression for the volume of L feet of drainage tubing, in cubic feet is:

\frac{1}{36}\pi L

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\bold{\huge{\blue{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • <u>The </u><u>right </u><u>angled </u><u>below </u><u>is </u><u>formed </u><u>by </u><u>3</u><u> </u><u>squares </u><u>A</u><u>, </u><u> </u><u>B </u><u>and </u><u>C</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>B</u><u> </u><u>has </u><u>an </u><u>area </u><u>of </u><u>1</u><u>4</u><u>4</u><u> </u><u>inches </u><u>²</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>C </u><u>has </u><u>an </u><u>of </u><u>1</u><u>6</u><u>9</u><u> </u><u>inches </u><u>²</u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u><u>A</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

The right angled triangle is formed by 3 squares

<u>We </u><u>have</u><u>, </u>

  • Area of square B is 144 inches²
  • Area of square C is 169 inches²

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{ Area \: of \: square =  Side × Side }

Let the side of square B be x

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 144 =  x × x }

\sf{ 144 =  x² }

\sf{ x = √144}

\bold{\red{ x = 12\: inches }}

Thus, The dimension of square B is 12 inches

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Area of square C = 169 inches

Let the side of square C be y

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 169 =  y × y }

\sf{ 169 =  y² }

\sf{ y = √169}

\bold{\green{ y = 13\: inches }}

Thus, The dimension of square C is 13 inches.

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The dimensions of square be is x and y

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  • Perpendicular = z
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<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ (z)² + (x)² = (y)² }

\sf{ (z)² + (12)² = (169)² }

\sf{ (z)² + 144 = 169}

\sf{ (z)² = 169 - 144 }

\sf{ (z)² = 25}

\bold{\blue{ z = 5 }}

Thus, The dimensions of square A is 5 inches

<h3><u>Therefore</u><u>,</u></h3>

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\sf{ = Side × Side }

\sf{ = 5 × 5  }

\bold{\orange{ = 25\: inches }}

Hence, The area of square A is 25 inches.

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