What is the solution to

The box plots below show the average daily temperatures in January and December for a U.S.

Marysya12 [62]

Answer:

The answer is C

Step-by-step explanation:

Took the test!

3 0

2 years ago

Peter inherits 15.000 dollars and place money with a bank. The interest rate are 3 percent. How many money will he get after 1ye

NeTakaya

The simplest form of an interest equation is A = P(1+rt)

where A = the total amount of money at the end, P = the principal (or amount of money you started with), r = the rate in percent, and t = the time in years.

In this case, P = 15000, r = 0.03 (because 3% in decimal form is 0.03), and t = 1:

$A=P(1+rt)\\A=15000(1+0.03*1)\\A=15000(1+0.03)\\A=15000(1.03)\\A=15450$

So, after 1 year he will get $15450 back, making him $450 more.

5 0

3 years ago

A tota of 17,100 seats are available for the next hockey game if 62% of the tickets are sold out how many seats are in the arena

Ainat [17]

Take 17100 divide by 100 the answer you get is the number of seats for 1% so to get 62%, multiply 17100/100 X 62 <span>the answer is certainly 45,000</span>

5 0

3 years ago

Read 2 more answers

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$