Answer:
-$1000
Step-by-step explanation:
(3800 - x)*3.5/100 = (3800 + x)*6/100
(3800 - x)7/200 = 3/50(3800 + x)
3800 - x = 12/7(3800 + x)
3800 - x = 45600/7 + 12x/7
(19x + 19000)/7 = 0
19x = -19000
x = -$1000.
The minus implies that the investment must occur in the first account, not the second. It wouldn't make sense to add more money into the second account, because the second account already exceeds the $188 interest with the amount it has in there. Therefore $1000 must be added from the second account and invested into the first.
Answer:
x = 4 or x = (-3)/2
Step-by-step explanation:
Solve for x over the real numbers:
2 x^2 - 5 x - 12 = 0
x = (5 ± sqrt((-5)^2 - 4×2 (-12)))/(2×2) = (5 ± sqrt(25 + 96))/4 = (5 ± sqrt(121))/4:
x = (5 + sqrt(121))/4 or x = (5 - sqrt(121))/4
sqrt(121) = sqrt(11^2) = 11:
x = (5 + 11)/4 or x = (5 - 11)/4
(5 + 11)/4 = 16/4 = 4:
x = 4 or x = (5 - 11)/4
(5 - 11)/4 = -6/4 = -3/2:
Answer: x = 4 or x = (-3)/2
I'm very sure the answer would be (4, 64)
Answer:
12 weeks
Step-by-step explanation:
Josiah and kiri are each saving money josiah starts with 100$ in savings accound and adds 5$ per week . Kiri with 40$ in her savings account adds 10$ each week after how weeks Josiah and kiri will have the same amount of money in their savings account
Josiah:
100 + 5w
Kiri:
40 + 10w
Where,
w = number of weeks
After how weeks Josiah and kiri will have the same amount of money in their savings account
Equate the savings of the both of them
100 + 5w = 40 + 10w
100 - 40 = 10w - 5w
60 = 5w
w = 60/5
= 12
w = 12 weeks
Josiah and kiri will have the same amount of money in their savings account after 12 weeks
