All categories

3 years ago

Draw and label point W. Draw and label line XY. Draw and label a plane K

Mathematics

1 answer:

mafiozo [28]3 years ago

3 0

Answer:

b a pex

Step-by-step explanation:

You might be interested in

The table shows the number of high school employees by gender and position, what percent of the

miss Akunina [59]

Answer: 22%

Step-by-step explanation:

6 0

3 years ago

158÷37 show work need help

denis-greek [22]

Here’s a pic of my work, it shows that the numbers 2,7,0 repeat.

Hope this helps!! :)

8 0

2 years ago

Convert to standard form.<br> y-5=-3(x+2)

Paul [167]

Answer:

Step-by-step explanation:

y-5=3(x+2)

y-5=3x+6

y-5-6=3x+6-6

y-1=3x

7 0

3 years ago

A 110 point final exam is made up of 50 question some questions are worth 4 points. How many of each type of question are on the

velikii [3]

There were 5 four point questions and There were 45 two point questions

4 0

3 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago