5 dived by 1 over 10

Mathematics

2 answers:

d1i1m1o1n [39]3 years ago

8 0

2 in a decimal form 2/1

MakcuM [25]3 years ago

5 0

50. You’d multiply by the reciprocal, which is 10z

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S the expression x3•x3•x3 equivalent to x3•3•3

Artyom0805 [142]

Remember
(x^m)(x^n)=x^(m+n)
and difference of 2 perfect squres
(a²-b²)=(a-b)(a+b)
and sum or difference of 2 perfect cubes

so
(x^3)(x^3)(x^3)=x^(3+3+3)=x^9
so

x^9=3*3*x^3
x^9=9x^3
minus 9x^3 both sides
0=x^9-9x^3
factor
0=(x^3)(x^6-9)
factor difference of 2 perfect squraes
0=(x^3)(x^3-3)(x^3+3)
factor differnce or sum of 2 perfect cubes (force 3 into (∛3)³)
0=(x³)(x-∛3)(x²+x∛3+∛9)(x+∛3)(x²-x∛3+∛9)
set each to zero

x³=0
x=0

x-∛3=0
x=∛3

x²+x∛3+∛9=0 has no solution

x+∛3=0
x=-∛3

x²-x∛3+∛9=0 has no solution

so the solutions are
x=-∛3, 0, ∛3

3 0

4 years ago

$7.50 admission; 20% off

kirill [66]

If you were getting 20% off of a £7.50 admission the new price would be £5.
This is due to the fact that 10% is 0.75
You can get 10% by dividing the number by 10.
10% doubled to get 20% is £1.50
7.50 minus the 20% off, 1.50, would be £5.

5 0

4 years ago

What is the image point of (-12, -8) after the transformation R270° 0 D. ?

Gennadij [26K]

Given:

The point is (-12,-8).

Rule of transformation is $R_{270^\circ}\circ D_{\dfrac{1}{4}}$ .

To find:

The coordinates of image after transformation.

Solution:

According to the rule of transformation $R_{270^\circ}\circ D_{\dfrac{1}{4}}$ , first the point is dilated by factor $\dfrac{1}{4}$ with origin as center of dilation after that it was rotated 270 degrees anticlockwise.