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Vlad1618 [11]
3 years ago
11

A jar contains 4 red marbles, 3 green marbles, 2 white marbles, and 1 purple marble. You randomly grab 5 marbles. Of the groups

of the selected 5 marbles, how many will have at least one white marble?
Mathematics
1 answer:
Fiesta28 [93]3 years ago
6 0

Answer:

126

Step-by-step explanation:

To calculate this, we need to assume at least one white marble will be picked... so let's take it out of the bag. Then we need to pick 4 more marbles... it's just then a combination calculation.

How many marbles is there in total?  4 + 3 + 2 + 1 = 10

We do just as if we had removed one white marble from the bag... so that leaves 9 in the bag.

We have to pick 4 out of those 9.... so, it's simple combination calculation:

C(9,4) = 9! / (4! (9--4)!) = 9! / (4! 5!) = 126

Some of those grabs will have 2 white marbles... but we're assured that there are 126 ways to combine the 10 marbles so there's at least one white in the 5 picked (since we forced it in our calculations).

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We can solve this limit in two ways.

<h3>Way 1:</h3>

By comparison of infinities:

We first expand the binomial squared, so we get

                         \large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}

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<h3>Way 2</h3>

Dividing numerator and denominator by the term of highest degree:

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                                \large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} }  }{\frac{1}{x}-\frac{5}{x^{4} }  }  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

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