Answer:
4y^2-6y+24
Step-by-step explanation:
add like-terms with polynomials (Khan Academy) had really good videos on specific examples
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Answer:
the new equation is f(x)=x^2-4
vertex- (0,-4)
zeros- (-2,2)
y-intercept- (-4)
and it has a minimum
Step-by-step explanation:
Answer:
x = -1
Step-by-step explanation:
When an exponent is negative, you have to move it to the denominator (or to the numerator if it's already on the denominator). Since the answer is 
, you know that the 2 has been raised to the power of 1 (any number to the power of 1 is the same number), so you just make it negative. Hope that helps!
