Q = recessive allele frequency = 0.3, and thus in H-W equilibrium there are ONLY two alleles, q (recessive) and
p (dominant). Therefore all of the p and q present for this gene in a population must account for 100% of this gene's alleles. And 100% = 1.00.
So p, the dominant allele frequency, must be equal to 1 - q --> p = 1 - q
p = 1 - 0.3 = 0.7.
Since heterozygotes are a combination of the p and q, we must again look at the frequencies of each genotype: p + q = 1, then (p+q)^2 = 1^2
So multiplying out (p+q)(p+q) = 1, we get: p^2+2pq+q^2 = 1 (all genotypes), where p^2 = frequency of homozygous dominant individuals, 2pq = frequency of heterozygous individuals, and q^2 = frequency of homozygous recessive individuals.
Therefore if the population is in H-W equilibrium, then the expected frequency of heterozygous individuals = 2pq = 2(0.7)(0.3)
2pq = 2(0.21) = 0.42, or 42% of the population.
Hope that helps you to understand how to solve population genetics problems!
The answer is mitochondria
The progression of a cell by the cycle of cell is regulated by the protein family Cyclic
Explanation:
- In the year 1982, Cyclin was located by Timothy Hunt as a family of proteins which has a vital function in the progression of a cell.
- CDK enzymes or ‘cyclin dependent kinase’ gets activated by it that synthesizes the cycle of the cell.
- The concentration of this protein moves in a cyclic way in the cell cycle. No enzymatic function is seen in them but it aims at CDK’s different location.
Doppler effect and redshift as the light coming from stars from the distance can be shifted in the same way as a pitch of sound does
If I’m not mistaking it’s the 2nd one plant cell
