Answer:
second law
Explanation:
becuz it states that force os directly proportional to the product of acceleration and mass
f=mxa
Answer:
c)polymerase chain reaction (PCR).
Explanation:
Because the paleontologist recovered only a bit of tissue and it is very old, it is very likely that the DNA in the sample is very small and part of it is degraded. Anyway, the paleontologist must first amplify the DNA sample to obtain many identical copies of the specific region of the DNA they want to compare. the above is done through a polymerase chain reaction (PCR).
Answer:
If an inhibitory synapse fires at the same time and at the same distance from the initial segment as an excitatory synapse of the same intensity there will be no changes in the potential in the firing zone.
Explanation:
Under normal conditions, the transmembrane potential depends on the ionic charges present in the intracellular and extracellular spaces. The extracellular space load is usually positive and in the cytoplasm is negative.
- <u>Depolarization</u> occurs by opening ion channels that allow sodium to enter the cell, making the intracellular space more positive.
- An opening of potassium channels releases this ion to the extracellular space, leading to <u>hyperpolarization</u>.
An excitatory synapse is one capable of depolarizing a cell and boosting the production of action potential, provided it is capable of reaching the threshold of said potential.
On the other hand, an inhibitory synapse is able to hyperpolarize the cell membrane and prevent an action potential from originating, so that they can inhibit the action of an excitatory synapse.
The interaction between two synapses, one excitatory and one inhibitory, -called synapse summation- will depend on the strength that each of them possesses. In this case, the intensity of both synapses being the same, there will be no changes in the membrane potential in the firing zone.
Learn more:
Excitatory and inhibitory postsynaptic potentials brainly.com/question/3521553
Answer:
38 ATP
Explanation:
On complete oxidation of one molecule of glucose yields 38 ATP. Break up of energy production is given below:
- During glycolysis 2 ATP and 2 NADH is produced.
- During formation of Acetyl CoA, 2 NADH is produced.
- During Citric Acid Cycle, 2 ATP, 6 NADH, 2 FADH₂ are produced.
Finally during Electron transport chain, reduced coenzymes NADH and FADH₂ oxidised to release ATP. Each NADH produce 3ATP and each FADH₂ produces 2 ATP. Altogether 10 NADH is produced during entire process of cellular respiration which yield 30 ATP and 2 FADH₂ yields 4 ATP. Therefore, on complete oxidation of one molecule of glucose yields 38 ATP.
