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Nataly [62]
4 years ago
11

What is 5 and 1/6 as an a/b fraction form.

Mathematics
2 answers:
natali 33 [55]4 years ago
5 0
5 1/6 is a mixed number. To put it into a/b fraction form means converting it to an improper fraction.

Multiply the denominator by the whole number then add the numerator. Put that over the original denominator.

5 1/6 = 6•5+1/ 6 = 31/6
il63 [147K]4 years ago
5 0
5 means there is 5 wholes a single whole in this case is 6/6 so do 6x5=30 plus the additional 1 would make 31/6 the correct improper fraction
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Regina has a bag of marbles that contains 3 blue marbles, 4 red marbles, and 5 yellow marbles. She draws one marble, then replac
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Answer:  

Possible outcomes=12

P(\text{Blue marble first})=\frac{1}{4}

P(\text{Yellow marble})=\frac{5}{12}

P(\text{ Blue then yellow})=\frac{5}{48}

Step-by-step explanation:

We can see these two events are independent as Regina replaced marble after drawing one marble.

We can find possible outcomes by adding number of blue, red and yellow marbles.

\text{Possible outcomes}=3+4+5=12

Let us find probability of getting a blue marble on first draw.

P(\text{Blue marble})=\frac{3}{(3+4+5)} =\frac{3}{12} =\frac{1}{4}

Now we will find probability of getting yellow marble.

P(\text{Yellow marble})=\frac{5}{(3+4+5)} =\frac{5}{12}

We can find probability of getting a blue marble and then yellow marble by multiplying both probabilities.

P(\text{ Blue then yellow})=\frac{1}{4}* \frac{5}{12} =\frac{5}{48}

Therefore, probability of getting a blue marble and then yellow marble is \frac{5}{48}.

6 0
4 years ago
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A golf team's 6 members had the scores below in their most recent
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Answer:

mean=81

SD=16.53

n=6

min=70

Q1=72

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Step-by-step explanation:

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3 years ago
(7k^4)(3k^9) what is the answer to this problem
sergey [27]

Answer:

21k^13

Step-by-step explanation:

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C o.75,0.5 yes it is 



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4 years ago
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A random sample of medical files is used to estimate the proportion p of all people who have blood type b.
makvit [3.9K]

Answer:

a) 106

b) 53

Step-by-step explanation:

Minimum required medical files can be found using the formula

n≥ p×(1-p) × (\frac{z}{ME} )^2 where

  • n is the minimum required medical files
  • p is the estimated proportion for blood type b
  • z is the corresponding z-score for two tailed 85% confidence level
  • ME is the margin of error in the estimation

For the case (a)

If there is no preliminary estimate for p, then it is estimated as p=0.5

corresponding z-score for two tailed 85% confidence level is 1.44

and ME is 0.07.

Putting all in the formula;

n≥ 0.5×0.5 × (\frac{1.44}{0.07} )^2  ≈ 106

For the case (b)

The only difference is p=\frac{13}{90}≈0.144

n≥ 0.144×0.856 × (\frac{1.44}{0.07} )^2  ≈ 53

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