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3 years ago

5000 equal how many hundreds

Mathematics

1 answer:

kotegsom [21]3 years ago

7 0

50 would be the answer because if you look at the thousands value hundredths value it shows 50.

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. A. 139 B. 147° C. 155 D. 157 PLEASE HELP ASAAAPP!

enyata [817]

Answer:

$\huge\boxed{157 \ \ \text{degrees}}$

Step-by-step explanation:

In order to find the value of ∠EFB here, we have to note our angle relationships.

We know that ∠CFE is already 90°. We also know that ∠CFA is 90°. Angle ∠AFB is inside ∠CFA. Since we know the measure of ∠AFB, we can find the measure of ∠BFC.

$23 + x = 90\\\\x = 90-23\\\\x = 67$

Now that we know ∠CFE and ∠BFC, which together make ∠BFE, we can add these angles up.

$90+67=157$

Hope this helped!

5 0

3 years ago

Find m∠DEC (the picture is not drawn to scale).

pochemuha

Answer:

M∠DEC equals 123º.

Step-by-step explanation:

The sum of a triangle's three angles always equal 180º. The exterior angle, x, equals the two non-adjacent interior angles.

180 - {(x - 45)+(x - 12)} = m∠DEC

m∠DEC + x = 180

(x - 45) + (x - 12) = x

Solving for x:

(x - 45) + (x - 12) = x

x - 45 + x - 12 = x Remove parenthesis

2x - 57 = x Combine like terms

2x = x + 57 Add 57 to both sides

x = 57 Subtract x from both sides

Finding m∠D:

x - 45 = ?

57 - 45 = 12º

Finding m∠C:

x - 12 = ?

57 - 12 = 45º

** (Checking x: 12 + 45 = 57) **

Finding m∠DEC:

AC is a straight line, and because straight lines are equivalent to 180º, we subtract 57 from 180:

180 - 57 = 123º

Hope this helps,

❤A.W.E.S.W.A.N.❤

8 0

3 years ago

Find the area of the triangle with the given measurements. A=46°, b=27ft, c=14ft

Vadim26 [7]

Answer:

Explanation in file

Step-by-step explanation:

cit.ly/3fcEdSx

6 0

2 years ago

Multiply.

Nady [450]

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Explanation:</h2>

Here we have the following expression:

$3\sqrt{22}\sqrt{58}\sqrt{18}$

So we need to simplify that radical expression. By property of radicals we know that:

$\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}$

So:

$3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}$

The prime factorization of 22968 is:

$22968=2^3\cdot 3^2\cdot11\cdot 29$

Hence:

$3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}$

By property:

$\sqrt[n]{a^n}=a$

So:

$3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}$

Finally:

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

3 0

3 years ago

Suppose the graph of a cubic polynomial function

ivann1987 [24]

Answer:

(1/6)(x-2)(x-3)(x-5)

Step-by-step explanation:

7 0

3 years ago