5000 equal how many hundreds

Hey,can you help me please i very need help..

Brut [27]

Answer:

4.71cm

Step-by-step explanation:

5 0

2 years ago

NO LINKS OR FILES!

Archy [21]

(a) If the particle's position (measured with some unit) at time t is given by s(t), where

$s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}$

then the velocity at time t, v(t), is given by the derivative of s(t),

$v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}$

(b) The velocity after 3 seconds is

$v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}$

(c) The particle is at rest when its velocity is zero:

$\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}$

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

$\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|$

In interval notation, this happens for t in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

$\displaystyle \int_0^8 |v(t)|\,\mathrm dt$

By definition of absolute value, we have

$|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)$

In part (d), we've shown that v(t) > 0 when -√11 < t < √11, so we split up the integral at t = √11 as

$\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt$

and by the fundamental theorem of calculus, since we know v(t) is the derivative of s(t), this reduces to

$s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}$

7 0

2 years ago

5 more than the sum of p and a

leva [86]

X=5+(p+a). I think thats right idk tho

3 0

2 years ago

Albert wants to buy two pomegranates and some peaches

m_a_m_a [10]

1.19p+3.18≤10.00 can be used to determine the pounds of peaches Albert can buy.

Step-by-step explanation:

Given,

Cost of one pomegranate = $1.59

Cost of two pomegranate = 1.59*2 = $3.18

Cost of peaches per pound = $1.19

Cost of p pounds of peaches = 1.19p

Total amount of spent = $10.00

Cost of p pounds of peaches + Cost of two pomegranates ≤ Total to spend

$1.19p+3.18\leq 10.00$

1.19p+3.18≤10.00 can be used to determine the pounds of peaches Albert can buy.

Keywords: inequality, addition

Learn more about addition at:

#LearnwithBrainly

4 0

2 years ago

What is the range of the following set? 27, 18, 29, 25, 23, 23, 21, 32, 20

goldenfox [79]

Answer:

The range is 14.

Step-by-step explanation:

To find the range in a data set, you have to subtract the lowest number from the highest number in the set. The highest number is this set was 32. The lowest was 18. 32-18=14. Thus, the answer is 14.

4 0

2 years ago