Question

What is the solution to the equation StartFraction 3 Over m + 3 EndFraction minus StartFraction m Over 3 minus m EndFraction = StartFraction m squared + 9 Over m squared minus 9 EndFraction? m = 3 m = 6 all real numbers no solution

Answer 1

Answer:

D on Edge2020 (No solution)

Step-by-step explanation:

Answer 2

Answer:

No solution.

Step-by-step explanation:

Given fraction is:

$\dfrac{3}{m+3} -\dfrac{m}{3-m} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3}{m+3} +\dfrac{m}{m-3} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3\times (m-3)+ m(m+3)}{(m+3)(m-3)} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3 m-9+ m^2+3m}{m^2-9} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{m^2-9+ 6m}{m^2-9} = \dfrac{m^2+9}{m^2-9}\\If\ m^2-9 \neq 0\ or\ m \neq 3\\\Rightarrow m^2-9+ 6m = m^2+9\\\Rightarrow 6m = 18\\\Rightarrow m = 3$

Formula used:

$(a+b)(a-b) = a^{2} -b^{2}$

But, the above equation was solved at the condition that:

$m\neq 3$

So, there is no solution for the given equation.