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2 years ago

10

The tree diagram below illustrates the possible outcomes of three tosses of a balanced coin. What is the probability that “heads

” will come up exactly two out of three times
A.1/8
B.1/4
C.3/8
D.1/2

1 answer:

antiseptic1488 [7]2 years ago

5 0

I’m pretty sure its B.1/4

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13. Write a few sentences describing what you have learned about the mean length of the population of 268 words in the Gettysbur

alexira [117]

You can obtain information about the mean population by taking a random sample of it and taking the average of that sample. The Law of big Numbers says that the bigger the sample, the more likely we will be closer to the real mean value. In other words, the margin of error is less likely to be big.

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2 years ago

3(v + 2) + 4 = 13<br> HELP ME!!

Zolol [24]

3(v + 2) + 4 = 13

Mutiply the bracket by 3

(3)(v)= 3v

(3)(2)= 6

3v+6+4= 13

3v+10=13

Move +10 to the other side

Sign changes from +10 to -10

3v+10-10= 13-10

3v= 13-10

3v= 3

divide both sides by 3

3v/3= 3/3

v= 1

Answer : v= 1

4 0

3 years ago

Read 2 more answers

PLEASE HELP!! I WILL AWARD BRAINLIEST AND 50 POINTS!!!!!!!!!!!!!!!!!!!!!! For the given picture: a) List all of the triangles th

PIT_PIT [208]

Answer:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters. If your teacher just wants one, it would be the middle one. (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB. For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD. For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO. For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB. For OBF, it’s BOC and OCB

Step-by-step explanation:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters. If your teacher just wants one, it would be the middle one. (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB. For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD. For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO. For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB. For OBF, it’s BOC and OCB

6 0

3 years ago

Solve for w<br> S=2(lw +lh+wh)

Maksim231197 [3]

<span>Solve for w
S=2(lw +lh+wh)

</span> $x = \frac{S - 2hl }{2(h + l)}$

7 0

2 years ago

Solve the system of equations.

Xelga [282]

Answer:

b. x=1, y=2, z=3

Step-by-step explanation:

The system of equations ...

3x +2y +z = 10
9x -6y +z = 0
x -y -3z = -10

has solution (x, y, z) = (1, 2, 3) . . . . matches choice B.

_____

While it is convenient to solve this using a graphing calculator or web site, one can easily solve the system by hand.

Subtract the second equation from 3 times the first:

3(3x +2y +z) -(9x -6y +z) = 3(10) -(0)

12y + 2z = 30 . . . . simplify

Dividing this result by 2 gives ...

6y +z = 15 . . . . . . [eq4]

Subtract 3 times the third equation from the first:

(3x +2y +z) -3(x -y -3z) = (10) -3(-10)

5y +10z = 40 . . . . simplify

y + 2z = 8 . . . . . . . divide by 5 . . . . . [eq5]

The two equations [eq4] and [eq5] can be solved any of the ways you usually solve two equations in two variables. Here, we'll use the first equation to write an expression for z that we can substitute into the second equation.

z = 15 -6y . . . . . subtract 6y from [eq4]

y + 2(15 -6y) = 8 . . . . . substitute for z in [eq5]

-11y +30 = 8 . . . . . simplify

-11y = -22 . . . . . . . subtract 30

y = 2 . . . . . . . . . . . divide by the coefficient of y

z = 15 -6(2) = 3 . . . . substitute for y in our equation for z

Substituting these values for y and z into the third original equation gives ...

x - 2 -3(3) = -10

x -11 = -10 . . . . . . . . simplify

x = 1 . . . . . . . . . . . . add 11

The solution to the above system of equations is (x, y, z) = (1, 2, 3).

_____

<em>Comment on the problem statement</em>

Math is generally unforgiving of imprecision. The given system of equations has no variable "z", and some other typos are apparently involved. That is why we rewrote the system to the equations shown above.

It is very easy to mistake z for 2, or g for 9, or o for 0, or 1 for 7. There are other confusions that are possible, as well. Letters I (eye) and l (ell) are easily confused, and may be confused with 1 (one) as well. Sometimes y and 4, or 4 and 9, can also be written so as to be difficult to tell apart. Great care must be taken when handwriting these symbols.

7 0

3 years ago