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4 years ago

Write an equation for the nth term of the arithmetic sequence

Mathematics

1 answer:

aleksklad [387]4 years ago

4 0

15) n+4
16) n-6
17) n+3
18)n-2
19)n+6
20) n-8

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Sidney cuts 6 slices of bread. She splits them evenly among p plates. Write an expression that shows how many slices are on each

fiasKO [112]

Answer: $\frac{6}{P}$

Step-by-step explanation:

$\\$ Since she splits them evenly , it means she splits them equally.

$\\$ The number of slice in each plate will be the total number of slices divided by the number of plates.

$\\$ The total number of slice = 6

$\\$ The total number of plates = P

$\\$ So , in each plate we have $\frac{6}{P}$ slices

7 0

3 years ago

Help me out please simple

const2013 [10]

A straight line is 180 degrees in measure

The straight line is made up of three angles

--> angle 1

--> angle 2

--> angle with a little square on it

(angle with a little square means it is 90 degrees in measure)

Let's set up an equation

$angle1 + angle2 + 90 = 180\\angle1 + 87 + 90 = 180\\angle1 = 3$

Thus angle 1 is 3 degrees or the second choice

Hope that helps!

5 0

3 years ago

Bonjour pourriez vous m'aider avec cette équation du second degré? j'ai du mal à comprendre le concept. merci

olga_2 [115]

If a quadratic equation has solutions, the standard procedure will always work: given an equation like

$ax^2+bx+c=0$

The solutions (if any) are given by

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In your case, you have

$a=-9,\ b=0,\ c=1$

So the formula becomes

$x_{1,2} = \dfrac{\pm\sqrt{36}}{18}= \pm\dfrac{6}{18}=\pm\dfrac{1}{3}$

Anyway, this is quite a special case, because you're missing the linear term (since $b=0$ )

This means that you can solve equations like these more easily: rearrange the equation to make it look like $ax^2=c$ . In your case, it becomes

$9x^2=1$

Divide both sides by 9:

$x^2=\dfrac{1}{9}$

Now, you know that the square of a number equals 1/9. By definition, it means that this number is the square root of 1/9. Nevertheless, both the square root and its opposite are solutions of the equation, because the minus sign will cancel out when squaring.

So, in general, you have

$ax^2=c \iff x^2 = \dfrac{c}{a} \iff x=\pm\sqrt{\dfrac{c}{a}$