What is the solution for the system of equations? Use the substitution method to solve.
1 answer:
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Answer:
92
Step-by-step explanation:
Lab Scores are 84, 81, and 93
Test Scores are 89 and 94
Each lab counts once and each test counts as two labs. At the end of the semester there is a final lab that counts as three regular labs.
Total Number of Labs= (3X1)+(2X2)+(1X3) =3+4+3 =10
To recieve an A(90), the average of her scores must be 90.
Let her final lab score =b
Refer to the attached diagram
Total Score=624+3b
For her average =90
Cross multiplying
624+3b =90 X 10
624+3b =900
3b =900-624
3b =276
Dividing both sides by 3
b= 92
She must score 92 in her final lab to receive an A.
