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Zolol [24]
3 years ago
6

Ms. Holmstrom set up a math problem to find out how much money her class spends for lunches at the cafeteria for over a 2-day pe

riod. On Monday, 14 students bought lunches in the cafeteria, and 16 students bought lunches on Tuesday. If lunches cost $2.50 each, how much money has Ms. Holmstrom's class spent?
Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0
Bsnslakwkwkwnanwnw. And
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If I have an assignment that is giving 48 points and I only get 29 what percentage is that
maw [93]

29/48 is about 60 percent to the nearest hundredth

4 0
3 years ago
Read 2 more answers
Hose is 32 feet long 32 feet long it needs to be cut into pieces equaling 5’3” How many whole pieces can be cut into how many wh
luda_lava [24]

Answer:

6

Step-by-step explanation:

Question tests the ability to get quotient

Here, 32 ft is divided by 5’3”

Normally, ft is denoted by ' while inches is denoted by ". So we divide 32 ft by 5ft and 3 inches

First, we convert dimensions into similar units. To convert 5’3” to ft, we divide 3” by 12 hence 3÷12=0.25'

The total is now 5.25'

Now

32'÷5.25'=6.1538461538461

This means, we shall obtain 6 whole pieces with some remainder. Since the question needs the whole pieces only, then the answer is 6

3 0
2 years ago
Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2
evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}

Step # 1 : Swap the first and second matrix rows,

\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}

Step # 2 : Cancel leading coefficient in row 2 through R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1,

\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}

As you can see our solution is x = 15, y = - 11 or (15, - 11).

4 0
3 years ago
EDIT// answer below thank for the help -.-
HACTEHA [7]

Step-by-step explanation:

Move it it up 4 and then find your x intercepts.

Find the x intercepts.

-x^2 + 4 = 0

<u>Move the 4 over to the right</u>

-x^2 = -4

<u>Divide out the - </u>

\frac{-x^2}{-} = \frac{-4}{-}

x^2 = 4

<u>Take the square root of each side</u>

\sqrt{x^2} = \pm \sqrt{4}

x = \pm \sqrt 2

Our x intercepts are at (-2,0) (2,0)

8 0
3 years ago
Im having trouble figuring out what this question means |7| + -4=?
OverLord2011 [107]

Answer:

3

Step-by-step explanation:

It means absolute value 7 plus -4

This means that if it were a -7, it would become positive because it is under absolute value bars...since it is positive nothing changes

7-4= 3

7 0
2 years ago
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