1c+4s=112
1c=3s
3s+4s=112
7s=112
Storybook= $16
Answer:



Step-by-step explanation:
we have
step 1
Group terms that contain the same variable, and move the constant to the opposite side of the equation

step 2
Factor 5 left side

step 3
Complete the square



step 4
Rewrite as perfect squares

step 5



step 6

27y^3 -343 starts out with 27y^3, and 343 is the cube of 7. Thus, we know immediately that 27y3 -343 is the diffeence of two squares.
The appropriate rule is a^3 - b^3 = (a - b)(a^2 + ab + b^2).
Here, we have 27y3 -343 = (3y - 7)(9y^2 + 12y + 49)