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ANTONII [103]
3 years ago
11

Add 2/5 plus 27/9 -0

Mathematics
1 answer:
Leviafan [203]3 years ago
4 0
2/5 plus 27/9 minus 0 equals 0
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What decimal fraction is between 1.2 and 1.5
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1.2=1\frac{2}{10}=1\frac{2:2}{10:2}=1\frac{1}{5}\\\\1.5=1\frac{5}{10}=1\frac{5:5}{10:5}=1\frac{1}{2}\\\\1\frac{1}{5} < \boxed{1\frac{1}{4} < 1\frac{1}{3}}
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3 years ago
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At what point on the curve x^2 + y^2 = 9 is the tangent line vertical?
Gemiola [76]

x² + y² = 9 is the equation of a circle with center (0, 0) and radius 3.

This puts the vertices at (-3, 0), (3, 0), (0, -3), and (0, 3).

When is the tangent line vertical? <em>when it passes through the x-axis.</em>

Answer: (-3, 0), (3, 0)

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3 years ago
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Gala2k [10]

Answer:

divide 47.12 by 3.14

Step-by-step explanation:

that way it will give you an answe

6 0
3 years ago
A ball is shot into the air using a brand new super-high-tech robotic arm to help baseball players practice catch fly balls.
stepladder [879]

Answer:

69 feet

Step-by-step explanation:

we have

h(t)=-16t^{2}+64t+5

where

h(t) is the height of the ball

t is the time in seconds

we know that the given equation is a vertical parabola open downward

The vertex is the maximum

so

the y-coordinate of the vertex represent the maximum height of the ball

Convert the quadratic equation into vertex form

The equation in vertex form is equal to

y=(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

h(t)=-16t^{2}+64t+5

h(t)-5=-16t^{2}+64t

h(t)-5=-16(t^{2}-4t)

h(t)-5-64=-16(t^{2}-4t+4)

h(t)-69=-16(t^{2}-4t+4)

h(t)-69=-16(t-2)^{2}

h(t)=-16(t-2)^{2}+69

the vertex is the point (2,69)

therefore

The maximum height is 69 ft

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3 years ago
Need this by today! Pls help! Im desperate! I will give correct anwser brainliest!
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