Answer:
If we have a set of N elements:
{x₁, x₂, ..., xₙ}
The mean value (also called the average value) Is calculated as:
Average = (x₁ + x₂ + ... + xₙ)/n
So if x is the average of 13, -16 and 6 ( a total of 3 values)
x will be equal to:
x = (13 + (-16) + 6)/3 = (19 - 16)/3 = 3/3 = 1
x = 1
And we know that:
y = ∛8
Remember that:
2*2 = 4
and
4*2 = 8
then
2*2*2 = 2^3 = 8
then ∛8 = 2.
So we have:
y = ∛8 = 2
Now we can replace these values in the equation:
x^2 + y^3
replacing:
x = 1
y = 2
we get:
1^2 + 2^3 = 1 + 8 = 9
the assumption being that the endpoints are two continuous points in the pentagon, Check picture below.
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-1}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[2-(-1)]^2+[3-4]^2}\implies d=\sqrt{(2+1)^2+(3-4)^2} \\\\\\ d=\sqrt{9+1}\implies d=\sqrt{10}~\hfill \stackrel{\stackrel{~\hfill \stackrel{\textit{5 sides}}{}}{\textit{perimeter of the pentagon}}}{5\sqrt{10}}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_1%7D%7B-1%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B2%7D~%2C~%5Cstackrel%7By_2%7D%7B3%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B%5B2-%28-1%29%5D%5E2%2B%5B3-4%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%282%2B1%29%5E2%2B%283-4%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B9%2B1%7D%5Cimplies%20d%3D%5Csqrt%7B10%7D~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7B~%5Chfill%20%5Cstackrel%7B%5Ctextit%7B5%20sides%7D%7D%7B%7D%7D%7B%5Ctextit%7Bperimeter%20of%20the%20pentagon%7D%7D%7D%7B5%5Csqrt%7B10%7D%7D)
Answer:
Probability that detector B goes off is '0.615'
Step-by-step explanation:
Given that:
1) Probability that detector A goes off and detector B does not go off is 0.25.
2)Probability that detector A does not go off is 0.35.
3)Probability that detector A goes off is (1-0.35)=0.65
Assuming that
Probability that detector B goes off is 'p' Hence the probability that detector B does not goes off is (1-p)
Thus the probability that detector A goes off and detector B does not go off is product of the individual probabilities

Probability that detector B goes off is '0.615'
Answer:
I think it's the third one.
Answer:
It’s b.
Step-by-step explanation:
To get the slope of the line, you need to points. Two points you already have are (0,0) and (-5,6). So all you need to do is plug those points into slope equation (y1-y2 over x1-x2) 0-6 over 0+5 equals -6/5. The slope equals -6/5, and when you plug it into y=mx+b it equals y=-6/5x. Which is b.