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Reptile [31]
3 years ago
5

Write an equation for the line, given that M=5/6 and why intercept is (0,12)

Mathematics
2 answers:
Fudgin [204]3 years ago
6 0
The answer to the question

alisha [4.7K]3 years ago
4 0

By definition, the generic equation of the line is given by:

y = mx + b

Where,

m: slope of the line

b: cutting point with vertical axis

For this case we have:

m = \frac{5}{6}

b = 12

Thus, substituting in the generic equation of the line we have:

y = \frac{5}{6} x + 12

Answer:

The equation of the line is given by:

y = \frac{5}{6} x + 12

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ankoles [38]
20% of 59.99 is 11.998 so 11.99. 59.99 - 11.99 = 48. 48x4 is 192
192$
5 0
3 years ago
I can't figure out how to solve for x
Romashka [77]
The answer i got was x=2 :)

Step 1: Simplify both sides of the equation.
x−2 over 3−(x+3 over 5)=−1
Simplify: (Show steps)
2 over 15x+−19 over 15=−1
Step 2: Add 19/15 to both sides.
2 over 15x+−19 over 15+19 over 15=−1+19 over 15
2 over 15x=4 over 15
Step 3: Multiply both sides by 15/2.
(15 over 2)*(2 over 15x)=(15 over 2)*(4 over 15)
3 0
3 years ago
Pls I need help with this
tigry1 [53]

Answer:

umm I think I know hold on

6 0
3 years ago
If x>2, then x^2-x-6/x^2-4=
Viefleur [7K]
Consider the expression \frac{x^{2} -x-6}{ x^{2} -4}

To factorize the expression in the denominator we use difference of squares: x^{2} -4=x^{2} - 2^{2} =(x-2)(x+2)

To factorize x^{2} -x-6 we use the following method:

x^{2} -x-6=(x-a)(x-b)

where a, b are 2 numbers such that a+b= -1, the coefficient of x,

and a*b= -6, the constant.

such 2 numbers can be easily checked to be -3 and 2

(-3*2=6, -3+2=-1)

So x^{2} -x-6=(x-a)(x-b)=(x+3)(x-2)


 \frac{x^{2} -x-6}{ x^{2} -4}= \frac{(x+3)(x-2)}{(x-2)(x+2)}= \frac{x+3}{x+2}


\frac{x+3}{x+2}= \frac{x+2+1}{x+2}= \frac{x+2}{x+2}+ \frac{1}{x+2}=1+ \frac{1}{x+2}

for x>2

\frac{1}{x+2}\ \textless \  \frac{1}{2+2}= \frac{1}{4}

thus

for x>2, 

1+ \frac{1}{x+2}\ \textless \ 1+ \frac{1}{4}= \frac{5}{4}


Answer: 

for x>2

\frac{x^{2} -x-6}{ x^{2} -4} =  \frac{x+3}{x+2} \ \textless \  \frac{5}{4}, (but the expression is never 0)
8 0
3 years ago
50 POINTS FOR THIS ALGEBRA WORD PROBLEM
olga55 [171]

Let x,x+2,x+4,x+6 be 4 consecutive no then,

sum of first 3 no=4x+12

According to condition,

20 less than 5 times 4th= 4 more than sum of 1st,2nd and 3rd

5(x+6)-20=4+(sum of first 3 no)

5(x+6)-20=4+(4x+12)

5(x+6)-20=4x+16

5x+30-20=4x+16

5x+10=4x+16

5x-4x=16-10

x=6

So,

1st no=x=6

2nd no=x+2=8

3rd no=x+4=6+4=10

4th no=x+6=6+6=12

7 0
3 years ago
Read 2 more answers
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