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4 years ago

How does the length of the hypotenuse in a right triangle compare to the lengths of the legs?

Mathematics

2 answers:

gavmur [86]4 years ago

6 0

we know that

In a right triangle we have

two legs and one hypotenuse

Let

a,b -----> the legs of the right triangle

c-----> the hypotenuse of the right triangle (the greater side)

Applying the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

therefore

<u>the answer is</u>

The length of the hypotenuse squared is the length of one leg squared plus the length of another leg squared

-Dominant- [34]4 years ago

4 0

Length of hypotenuse= sum of squares of lengths of the legs

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-8÷+12×9-4×6÷56÷7×2

EastWind [94]

Answer:

$\frac{ - 300}{49}$

or -6.122

Step-by-step explanation:

In answering this kind of questions, you must take note of BODMAS. that is;

B - Bracket

O - Of (multiplication)

D - Division

M - Multiplication

A - Addition

S - Subtraction

and you have to answer by the order above to get the correct answer. thank you

hope it helps .

4 0

4 years ago

Read 2 more answers

YOU WILL GET 20pts. PLEASE IT IS ABOUT TRIGONOMETRY. GIVE ME WORKING OUT AS WELL PLEASSSSSSSSSSSSSSE

mixer [17]

Sin 20 is the answer
Using the trigonometry rule
Sin cos tan
Sin x = opposite side (a) / hypotenuse side (c)
A/c = sin x
x= 20 ( angle formed by side c and b )

6 0

3 years ago

The length of overline CD is 12 units. C^ prime D^ prime is the image of overline CD under a dilation with a scale factor of n.

Rufina [12.5K]

Answer:

A, D , and E

Step-by-step explanation:

We have that:

$\overline{CD} = 12 \: units$

$\overline{C'D'}$

is the image of CD after a dilation of scale factor n.

We use the relation between the image length and object length:

$\overline{C'D'} = n \times \overline{CD}$

Option A

If n=3/2, then

$\overline{C'D'} = \frac{3}{2} \times 12 = 3 \times 6 = 18 \: units$

This is true.

Option B

If n=4, then

$\overline{C'D'} = 4 \times 12 = 36 \: units$

This is false.

Option C

If n=8, then

$\overline{C'D'} = 8 \times 12 = 96 \: units$

This too is false.

Option D

If n=2, then

$\overline{C'D'} = 2 \times 12 = 24 \: units$

This is true

Option E

If n=3/4, then

$\overline{C'D'} = \frac{3}{4} \times 12$

$\overline{C'D'} = 3 \times 3 = 9 \: units$

This is also true.

4 0

3 years ago

A quarter back completes 29% of his passes. We want to observe this quarterback during one game to see how many pass attempts he

Ann [662]

Answer: P12* = 0.0164 or 1.64%

Therefore, the probability that it takes more than 12 attempts before he completes a pass is 0.0164 or 1.64%

Step-by-step explanation:

Given;

The quarterback's pass accuracy P= 29% = 0.29

The probability of not completing a particular pass P*

= 1 - 0.29 = 0.71

the probability that it takes more than 12 attempts before he completes a pass implies that the quarterback will not complete his first 12 pass attempts.

The probability that he will not complete the first 12 pass

P12* = (P*)^12

P12* = (0.71) ^12

P12* = 0.0164 or 1.64%

Therefore, the probability that it takes more than 12 attempts before he completes a pass is 0.0164 or 1.64%

5 0

4 years ago

Which transformation carries the pentagon onto its

svetoff [14.1K]

C it’s I think lol!!!!!^^*

6 0

3 years ago