Answer:
Step-by-step explanation:
We need to solve the quadratic equation
6 = x^2 -10x
Rearranging we get,
x^2-10x-6=0
Using quadratic formula to solve the quadratic equation
a= 1, b =-10 and c=6
Putting values in the quadratic formula
So, 
Answer:
the sum of 2 consecutive even integers is 66.
Step-by-step explanation:
This means that if one integers is x, the other must be either x-2 or x+2. Therefore, we can write 6=x+(×-2)=2×2. Solving for x, we can find ×=34. this means that the other integer is 34-2=32. indeed, 32+34=66, and done hope this helped C:
Answer:
solution is in attachment
hope it helps
First find the slope,
m=(y2-y1)/(x2-x1)=(1-(-9))/(7-6)=10
Next, use the point slope form to find the equation:
L : y-y1=m(x-x1) => y-1=10(x-7)
[in point slope form, point is (7,1), slope=m=10 ]
Answer:
H0: μd=0 Ha: μd≠0
t= 0.07607
On the basis of this we conclude that the mean weight differs between the two balances.
Step-by-step explanation:
The null and alternative hypotheses as
H0: μd=0 Ha: μd≠0
Significance level is set at ∝= 0.05
The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571
The test statistic under H0 is
t = d/ sd/ √n
Which has t distribution with n-1 degrees of freedom
Specimen A B d = a - b d²
1 13.76 13.74 0.02 0.004
2 12.47 12.45 0.02 0.004
3 10.09 10.08 0.01 0.001
4 8.91 8.92 -0.01 0.001
5 13.57 13.54 0.03 0.009
<u>6 12.74 12.75 -0.01 0.001</u>
<u>∑ 0.06 0.0173</u>
d`= ∑d/n= 0.006/6= 0.001
sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882
sd= 0.05368
t= 0.001/ 0.05368/ √6
t= 0.18629/2.449
t= 0.07607
Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.
