Ask question

Ask question

All categories

Yakvenalex [24]

3 years ago

12

Simplify the expression: (2m + 1)(2) =

2 answers:

Dima020 [189]3 years ago

8 0

4m+2

because 2mx2=4m and 1x2=2 so 4m+2

ra1l [238]3 years ago

8 0

Answer: 4m + 2

gvrfcedwx

You might be interested in

The question is in the picture

12345 [234]

For this case we have by definition that if two lines are parallel, then their slopes are equal.

We have the following line:

$-2x + 4y = 8$

Manipulating algebraically we have:

$4y = 8 + 2x$

$y = \frac {2x} {4} + \frac {8} {4}\\y = \frac {1} {2} x + 2$

Thus, the slope is $m = \frac {1} {2}$

Then, a parallel line will be of the form:

$y = \frac {1} {2} x + b$

We find the cut point "b" replacing the point:

$-1 = \frac {1} {2} (- 5) + b\\-1 = - \frac {5} {2} + b\\b = -1 + \frac {5} {2}\\b = \frac {-2 + 5} {2}\\b = \frac {3} {2}$

Finally, the line is:

$y = \frac {1} {2} x + \frac {3} {2}$

ANswer:

Option A

6 0

3 years ago

Please help :c <br><br> the first word is find

xeze [42]

Answer:

The values of $r_{2}$ and $\alpha_{2}$ are 2 and 150º.

Step-by-step explanation:

The complete statement is:

<em>Find </em> $\alpha_{2}$ <em> and </em> $r_{2}$ <em> such that </em> $\sin \theta - \sqrt{3}\cdot \cos \theta = r_{2}\cdot \cos (\theta - \alpha_{2})$ <em>. </em>

We proceed to use the following trigonometric identity:

$\cos (\theta - \alpha_{2}) = \cos \theta \cdot \cos \alpha_{2} +\sin \theta \cdot \sin \alpha_{2}$ (1)

$\sin \theta -\sqrt{3}\cdot \cos \theta = r_{2}\cdot \cos \theta \cdot \cos \alpha_{2}+r_{2}\cdot \sin \theta \cdot \sin \alpha_{2}$

By direct comparison we derive these expressions:

$r_{2}\cdot \sin \alpha_{2} = 1$ (2)

$r_{2}\cdot \cos \alpha_{2} = -\sqrt{3}$ (3)

By dividing (2) by (3), we have the following formula:

$\tan \alpha_{2} = -\frac{1}{\sqrt{3}}$

$\tan \alpha_{2} = -\frac{\sqrt{3}}{3}$

The tangent function is negative at second and fourth quadrants. That is:

$\alpha_{2} = \tan^{-1} \left(-\frac{\sqrt{3}}{3} \right)$

There are at least two solutions:

$\alpha_{2,1} = 150^{\circ}$ , $\alpha_{2,2} = 330^{\circ}$

And the value of $r_{2}$ :

$r_{2}^{2}\cdot \sin^{2}\alpha_{2} + r_{2}^{2}\cdot \cos^{2}\alpha_{2} = 4$

$r_{2}^{2} = 4$

$r_{2} = 2$

The values of $r_{2}$ and $\alpha_{2}$ are 2 and 150º.

5 0

3 years ago

How many mL are there in 3,700 microliters?

rewona [7]

Answer:

3.7 mL

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Pls help me solve this

dusya [7]

I thinks that the answer is 9

7 0

2 years ago

Read 2 more answers

What is<br> 2+2?<br> I been trying to figure it out, but I’m stuck on this question

Alexandra [31]

Answer:

4

Step-by-step explanation:

6 0

3 years ago