All categories

3 years ago

What do I do to start this problem.for #4

Mathematics

2 answers:

OLga [1]3 years ago

5 0

Well there is 1 girl for every 5 boys so you could add 1 + 5 to get 6, and divide the total students by 6 to get 38 girls.

I am Lyosha [343]3 years ago

3 0

Divide the 228 by 5 and you should get 45.6 or rounding, 46

So, there were 46 girls and 182 boys.

You can check by multiplying 46 by 5 and you will get 228

Hope this helped

You might be interested in

Solve this equation: <br> x/5=-7

Marianna [84]

Answer:

x/5 = -7

Step-by-step explanation:

x = -35

I used a calculator pls let me know if im incorrect

3 0

3 years ago

Read 2 more answers

Need help. i learned this already i jus need a refresher. thanks

Arisa [49]

Answer:

Step-by-step explanation:

4/5

4 0

3 years ago

I need help identifying if this is a 90,180,270 degree transformation

Arte-miy333 [17]

$\begin{gathered} Choosing\text{ one point} \\ K(-1,-4) \\ K^{\prime}(1,4) \\ It\text{ means} \\ K^{\prime}=K(-x,-y) \\ Hence \\ This\text{ is a 180\degree transformation} \end{gathered}$

6 0

1 year ago

2(3 + x) – x(7 + x)<br> if x = 3<br> Pls someone answer and work

diamong [38]

Answer:

the answer would be -18

Step-by-step explanation:

3+3=6 2×6=12. 7+3=10 3×10=30 12-30= -18

7 0

3 years ago

Read 2 more answers

Solve each system using elimination. tell whether the system has one solution, infinitely many solutions, or no solution.

Tomtit [17]

1.
$x-2y=-1 \\
2x+y=4 \ \ \ |\times 2 \\ \\
x-2y=-1 \\
\underline{4x+2y=8 \ } \\
x+4x=8-1 \\
5x=7 \\
x=\frac{7}{5} \\
x=1 \frac{2}{5} \\ \\
x-2y=-1 \\
\frac{7}{5}-2y=-1 \\
-2y=-1-\frac{7}{5} \\
-2y=-\frac{5}{5}-\frac{7}{5} \\
-2y=-\frac{12}{5} \\
y=\frac{6}{5} \\
y=1 \frac{1}{5} \\ \\
\boxed{(x,y)=(1\frac{2}{5}, 1 \frac{1}{5}) \Leftarrow \hbox{one solution}}$

2.
$x+3y=4 \ \ \ |\times 2 \\
2x-6y=8 \\ \\
2x+6y=8 \\
\underline{2x-6y=8} \\
2x+2x=8+8 \\
4x=16 \\
x=4 \\ \\
x+3y=4 \\
4+3y=4 \\
3y=4-4 \\
3y=0 \\
y=0 \\ \\
\boxed{(x,y)=(4,0) \Leftarrow \hbox{one solution}}$

3.
$y=-\frac{1}{2}x-3 \ \ \ |\times (-2) \\
x+2y=-6 \\ \\
-2y=x+6 \\
\underline{x+2y=-6 \ } \\
x=x+6-6 \\
x-x=6-6 \\
0=0 \\ \\
\boxed{\hbox{infinitely many solutions}}$

4.
$6x-3y=-18 \\
-2x+4y=18 \ \ \ |\times 3 \\ \\
6x-3y=-18 \\
\underline{-6x+12y=54} \\
-3y+12y=54-18 \\
9y=36 \\
y=4 \\ \\
6x-3y=-18 \\
6x-3 \times 4=-18 \\
6x-12=-18 \\
6x=-18+12 \\
6x=-6 \\
x=-1 \\ \\
\boxed{(x,y)=(-1,4) \Leftarrow \hbox{one solution}}$

3 0

3 years ago