Question

the dimensions of a smaller rectangle are 3ft by 9ft the dimensions of a larger rectangle are 5ft by 15ft find the ratio of the atea of the smaller rectangle to the area of the larger rectangle

Answer 1

The ratio of the area of the smaller rectangle to the area of the larger

rectangle is $\frac{9}{25}$

Step-by-step explanation:

The formula of the area of a rectangle is A = l × w, where l and w

are its dimensions

• The dimensions of a smaller rectangle are 3 ft by 9 ft
• The dimensions of a larger rectangle are 5 ft by 15 ft

We want to find the ratio of the area of the smaller rectangle to

the area of the larger rectangle

∵ The dimensions of the smaller rectangle are 3 ft and 9 ft

∴ The area of the smaller rectangle = 3 × 9 = 27 feet²

∵ The dimensions of the larger rectangle are 5 ft and 15 ft

∴ The area of the smaller rectangle = 5 × 15 = 75 feet²

Let us find the ratio of the area of the smaller rectangle to the area

of the larger rectangle

→ smaller rectangle  :  larger rectangle

→ 27                           :  75

Divide the both terms of the ratio by 3

→ 9                             :  25

The two terms of the ratio do not divisible by any other number

∴ The simplest form of the ratio is 9 : 25

∴ The ratio of the area of the smaller rectangle to the area of the larger

   rectangle = $\frac{9}{25}$

The ratio of the area of the smaller rectangle to the area of the larger

rectangle is $\frac{9}{25}$

Learn more:

You can learn more about the ratio in brainly.com/question/10781917

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