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3 years ago

Find arc length. (Ignore the pencil mark, NEED ASAP)

Mathematics

1 answer:

DerKrebs [107]3 years ago

3 0

Answer:

15.7 yd

Step-by-step explanation:

Arc length is given as 2πr(θ/360).

Where,

Radius (r) = 10 yd,

Measure of arc (θ) = 90°

π = 3.142

Arc length = 2*3.142*10(90/360)

Arc length = 62.84(¼)

Arc length = 62.84/4

Arc length = 15.71 yd

The act length is approximately 15.7 (to the nearest tenth)

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Which inequality represent the statement: John is at least 5 feet tall.

belka [17]

Answer:

$h\geq 5 \text{ feet}$

Step-by-step explanation:

Considering John's height as $h$ , saying that his height is at least 5 feet tall, it implies that the lowest height for John is $h=5$

So, inequality is

$h\geq 5 \text{ feet}$

7 0

2 years ago

Read 2 more answers

X² - y² = z²<br>Express y in terms of x and z.<br>

lord [1]

Answer:

y² = x² - z²

Step-by-step explanation:

x² - y² = z²

Transpose y the other side

x² - z² = y²

y² = x² - z²

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3 years ago

Read 2 more answers

Step 2: Radii OK and NL are perpendicular to OM because of the radius-tangent theorem. By definition of perpendicular, angles KO

solong [7]

Answer:

Angle Angle Angle (AAA) property

Step-by-step explanation:

A right angled triangle is a triangle that has one of its angles to equal $90^{0}$ . It could be in the form of an isosceles triangle or an acute angled triangle.

The given question compares the congruence properties of two triangles, KOM and LNM.

Thus,

<KOM = <LNM (right angle theorem)

<LMN = <KMO (common angles to both triangles)

⇒ <OKM = <NLM (property of a triangle i.e sum of angle in a triangle is $180^{0}$ )

ΔKOM = ΔLNM (congruence property)

Therefore, by angle angle angle (AAA) congruence property, the two triangles are similar.

7 0

3 years ago

the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const

laiz [17]

In general, the volume

$V=\pi r^2h$

has total derivative

$\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)$

If the cylinder's height is kept constant, then $\dfrac{\mathrm dh}{\mathrm dt}=0$ and we have

$\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}$

which is to say, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ are directly proportional by a factor equivalent to the lateral surface area of the cylinder ( $2\pi r h$ ).

Meanwhile, if the cylinder's radius is kept fixed, then

$\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}$

since $\dfrac{\mathrm dr}{\mathrm dt}=0$ . In other words, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dh}{\mathrm dt}$ are directly proportional by a factor of the surface area of the cylinder's circular face ( $\pi r^2$ ).

Finally, the general case ( $r$ and $h$ not constant), you can see from the total derivative that $\dfrac{\mathrm dV}{\mathrm dt}$ is affected by both $\dfrac{\mathrm dh}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ in combination.

8 0

2 years ago

Find the distance between two points (-3,2) and (3,0)

hammer [34]

Answer:

$\sqrt{40}$

Step-by-step explanation:

If we draw a right triangle, it would have legs 6 and 2.

8 0

3 years ago