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2 years ago

I need help :,)

Mathematics

2 answers:

Dmitry_Shevchenko [17]2 years ago

7 0

Answer:

add 17.50 to 8.75 you get 26.25

amid [387]2 years ago

5 0

Answer:

$26.25

Explanation:
add both numbers given

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Which system of inequalities is shown in the graph?

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Step-by-step explanation: Graph is shown down below.

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What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0

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Answer:

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}$

Hence, ption B is true.

Step-by-step explanation:

Given the expression

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

solving the expression

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

$\sqrt{x^2y^3}=xy\sqrt{y}$

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so the expression becomes

$\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}$

Group like terms

$=2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}$

Add similar elements

$=2xy^2\sqrt{x}+2xy\sqrt{y}$

Therefore, we conclude that:

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}$

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3 years ago

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Find the cost of painting a cubical block of side length 3.2 cm, if painting costs $5 per cm2.

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<h3><u>Answer</u>:- </h3>

$\longrightarrow \sf \$ \: 307.2$

<h3><u>Solution:-</u></h3>

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

$\green{ \underline { \boxed{ \sf{Surface \: area \:of \:Cube = 6a^2}}}}$

<u>where a is side of the cube </u>

$\begin{gathered}\\\quad \sf Surface \: area \:of \:Cube = 6\times(3.2)^2 \\\end{gathered}$

$\begin{gathered}\\\implies \quad \sf 6\times 3.2\times3.2 \\\end{gathered}$

$\begin{gathered}\\\implies \quad \sf 61.44 cm^2 \\\end{gathered}$

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$\maltese \sf Cost \:of \:painting \: 1 \: cm² = \$ 5$

$\sf Cost \: of \: painting \: 61.44 \:cm²=61.44×5$

$\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2$

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3 years ago

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Answer:c

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