The question requires that we have to state the hypothesis:
null hypothesis;H0: u1 < u2, the alternate hypothesis;H1: u1 > u2. The one tail test is what is to be used.
<h3>A.
How to state the hypothesis</h3>
H0: u1 < u2
H1: u1 > u2
The one tail test statistic is what is to be used here
<h3>B.
standard error </h3>
![\sqrt{\frac{30.8}{17} +\frac{6.1}{15} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B30.8%7D%7B17%7D%20%2B%5Cfrac%7B6.1%7D%7B15%7D%20%7D)
= 1.49
The df = 17 + 15 - 2
= 30
test statistic = 18.9 - 17.4 / 1.49
= 1.007
We have the critical value on excel as T.INV(0.9,30)
= 1.310
E. At 0.1, we can conclude that t-value (1.007) does not lies in the rejection area. We fail to reject the null hypothesis. Hence we conclude that the mean vacation with the unlimited plan is greater.
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Answer: 2.5
Step-by-step explanation:
I believe 2.5 because If we take y/x we have 4,10 so I divide.
Answer:
15.867
lbs or almost
16
lbs.
Step-by-step explanation:
Answer:2.91666666667
Step-by-step explanation:
Answer:
L = 70
W = 32
Step-by-step explanation:
P = 2L + 2W
P 204 feet
W = x
L = 2x + 6
P = 2L + 2W
P = 2*(2x + 6) + 2*x
P = 4x + 12 + 2x
P = 6x + 12
But we know that P = 204 So 6x + 12 = 204
6x + 12 = 204 Subtract 12 from both sides
6x + 12 - 12 = 204 - 12 Collect like terms on the right
6x = 192 Divide by 6
x = 192/6
x = 32
Answer
W = 32
L = 2*W + 6
L = 2*32 + 6
L = 64 + 6
L = 70