Our aim is to calculate the Radius so that to use the formula related to the area of a segment of a circle, that is: Aire of segment = Ф.R²/2
Let o be the center of the circle, AB the chord of 8 in subtending the arc f120°
Let OH be the altitude of triangle AOB. We know that a chord perpendicular to a radius bisects the chord in the middle. Hence AH = HB = 4 in
The triangle HOB is a semi equilateral triangle, so OH (facing 30°)=1/2 R. Now Pythagoras: OB² = OH² + 4²==> R² = (R/2)² + 16
R² = R²/4 +16. Solve for R ==> R =8/√3
OB² = OH² +
Answer: A. 6.12 cm; scalene
I think
Step-by-step explanation:
that's the answer i got.
Answer:
A'= (0,4)
B'= (-1,2)
C'= (2,1)
D'= (2,3)
Step-by-step explanation:
Hope that this helps! :)
Answer:
Work below
Step-by-step explanation:
49 total dogs.
36 more small dogs.
13 big dogs.
lol just realized today's school has sh*t wording and this question can be taken TWO ways. 36 more as in, 36 more dogs in total or 36 more small dogs than large dogs adding the amount of large dogs with this. this gives us 49.
the only way to get the x value (large dogs) and add this on top of the 36 (small dogs) and get 49 is to do 6.5 + 42.5 (36 + 6.5) this gives us 49.
Thanks guy in the comments for giving the second response, after some thinking i realized that i could also read it that way.
F** k today's hw and their wording
