Answer:
100-both
75-5
565- 5
2815- 5
10050- both
57- 3
1365- 3
14- 2
81- 3
3850- 2
333- 9
1125- 9
448- 8
630- 9
5496- 8
114- 6
21,750- 6
3580- 4
2528- 4
944- 4
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Answer:
0.1587
Step-by-step explanation:
Let X be the commuting time for the student. We know that
. Then, the normal probability density function for the random variable X is given by
. We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,
= 0.1587
To find this probability you can use either a table from a book or a programming language. We have used the R statistical programming language an the instruction pnorm(35, mean = 30, sd = 5, lower.tail = F)
The range is all positive values...
R{y | y>0}
Range > "Y" such that y is greater than 0