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Rashid [163]
2 years ago
15

Multiply −3x2(6x2 2x − 3). −18x2 − 6x 9 −18x4 − 6x3 9x2 3x2 − x − 6 3x4 − x3 − 6x2

Mathematics
2 answers:
alisha [4.7K]2 years ago
8 0
-3x^2(6x^2 + 2x - 3) = -18x^4 - 6x^3 + 9x^2
riadik2000 [5.3K]2 years ago
8 0

we have

-3x^{2} (6x^{2}+2x-3)

solve the multiplication

-3x^{2} (6x^{2}+2x-3)=(-3x^{2}*6x^{2})-(3x^{2}*2x)+(3x^{2}*3)\\=-18x^{4} -6x^{3}+9x^{2}

therefore

<u>the answer is</u>

-18x^{4} -6x^{3}+9x^{2}

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Write the fraction in simplest from 8/10
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How to solve which fraction is larger 10/13 or 11/14 or 14/15 or 17/18
alexandr402 [8]
To solve these type of problem you have to make the denominator the same or use the claculator.

let us do this problem by making the denominator the same.

\frac{10}{13} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{11}{14} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{14}{15}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{17}{18} \\\\ \frac{10}{13}\times \frac{3780}{3780} \ \ \ \ \ \ \ \ \ \frac{11}{14} \times \frac{3510}{3510} \ \ \ \ \ \ \ \ \ \frac{14}{15} \times \frac{3276}{3276} \ \ \ \ \ \ \ \ \ \frac{17}{18} \times \frac{2730}{2730}

\frac{37800}{49140} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    \frac{38610}{49140}  \ \ \ \ \ \ \ \ \ \ \ \ \ \    \frac{45864}{49140}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    \frac{46410}{49140}

So, now. the one with the largest numerator is the largest fraction

In this case, \frac{46410}{49140} is the largest which is equal to \frac{17}{18}.

So, the largest fraction is \frac{17}{18}.
5 0
3 years ago
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