Subtract 9a^2-6a+59a 2 −6a+59, a, squared, minus, 6, a, plus, 5 from 10a^2+3a+2510a 2 +3a+2510, a, squared, plus, 3, a, plus, 25
nasty-shy [4]
Answer:
The answer to your question is a² + 9a + 20
Step-by-step explanation:
10a² + 3a + 25 - (9a² - 6a + 5)
- Remove parentheses changing the sign of the second polynomial
10a² + 3a + 25 - 9a² + 6a - 5
- Group like terms
(10a² - 9a²) + (3a + 6a) + (25 - 5)
- Simplify and result
a² + 9a + 20
Step-by-step explanation:
(i) T = { 4, 8, 12}
U = {1,2,3,4,6,8,12,24}
(iii) TUU = {1,2,3,4,6,8,12,24}
(iv) yes, because all the elements in T are also the elements in U.
If you have a no solution choice that will be your answer because w+34=w-22
you would subtract w from both sides to get 34=-22 and that's not true therefore it would be a no solution equation.