Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
Answer:
Mmmmmmmmmmmmm.............
Step-by-step explanation:
MI no sabo amigo perdon
Answer:
∠y=60°
Step-by-step explanation:
Question says to find the measure of the angle Y.
We have been given a picture of triangle XYZ. All angles are marked with same sign so that indicates that all three angles are equal.
∠x = ∠y = ∠z...(i)
We know that sum of all three angles of the triangle is always 180°.
So we can write:
∠x+∠y+∠z=180°
∠y+∠y+∠y=180° {using equation (i) }
3∠y=180°
divide both side by 3
∠y=60°
Hence final answer is the measure of angle y is 60 degree.
