Answer:
63°
Step-by-step explanation:
Angle <2 and the angle with measure of 63 are alternate exterior angles and has same measurement.
For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: the amount a 10-11-year-old spends on a trip to the mall.
Assuming that the variable has a normal distribution, you have to construct a 98% CI for the average of the amount spent by the 10-11 year-olds on one trip to the mall.
For this you have to use a Student-t for one sample:
X[bar] ± *
n= 6
$18.31, $25.09, $26.96, $26.54, $21.84, $21.46
∑X= 140.20
∑X²= 3333.49
X[bar]= ∑X/n= 140.20/6= 23.37
S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/5[3333.49-(140.2)²/6]= 11.50
S= 3.39
X[bar] ± *
[23.37 ± 3.365 * ]
[18.66;29.98]
With a confidence level of 98%, you'd expect that the interval $[18.66;29.98] will include the population mean of the money spent by 10-11 year-olds in one trip to the mall.
I hope you have a SUPER day!
Answer: 107.5 square meters
Step-by-step explanation:
10x10.75=107.5