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Andrej [43]
3 years ago
8

Make u the subject of the formula D=ut + kt2

Mathematics
1 answer:
Yuliya22 [10]3 years ago
3 0
To make u the subject we proceed as follows:
D=ut+kt²
subtract kt² from both sides
D-kt²=ut+kt²-kt²

This will give us:
D-kt²=ut

next we divide both sides by t
(D-kt²)/t=ut/t

this will give us
u=(D-kt²)/t

simplifying the above we get:
u=D/t-kt

Answer: u=D/t-kt
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Use the graph to determine the domain and range of the relation and wether the relation is a function
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Answer:

C. Domain: {x|-8\le x\le8}, Range: all real numbers;No, it is not a function

Step-by-step explanation:

From the diagram in the attachment, the domain is  {x|-8\le x\le8}.

The reason is that, the furthest the graph could extend is 8 to the right and left of the y-axis.

The range of the relation is all real numbers. The reason is that, the graph extends up above and below the x-axis without bounds.

The relation is not a function, because its graph failed the vertical line test.

See graph

The correct answer is C.

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3 years ago
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RideAnS [48]
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Answer:

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Step-by-step explanation:

Since we already have an equation just plug in terms where needed.

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The gcf of 42 and 70 is 14
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